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zvonat [6]
3 years ago
12

Please help!!

Mathematics
2 answers:
icang [17]3 years ago
6 0

Answer:

  x = 24

Step-by-step explanation:

The segments on either side of an angle bisector are proportional:

  (x +4)/44.8 = 35/56

  x +4 = 44.8·(35/56) = 28 . . . . multiply by 44.8

  x = 24 . . . . . subtract 4

Alika [10]3 years ago
4 0

Answer:

The value of x is 24.

Step-by-step explanation:

Given information: In ΔGHE, ED is angle bisector, EG=44.8 millimeters, GD=(x+4) millimeters, DH=35 millimeters, and EH=56 millimeters.

According to the angle bisector theorem, an angle bisector divide the opposite side into two segments that are proportional to the other two sides of the triangle.

In ΔGHE, ED is angle bisector, By using angle bisector theorem, we get

\frac{GD}{DH}=\frac{EG}{EH}

\frac{x+4}{35}=\frac{44.8}{56}

Multiply both the sides by 35.

x+4=\frac{44.8}{56}\times 35

x+4=28

Subtract 4 from both the sides.

x=28-4

x=24

Therefore the value of x is 24.

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Tom [10]

Answer:

1102.5 pounds of apples will be sold in a week.

Step-by-step explanation:

Amount of apples in each bag = 3.5 pounds

If BJs sells 45 bags each day, amount of apples sold = 3.5 × 45

                                                                                        = 157.5 pounds

Number of days in a week = 7

Amount of apples sold in one week = Apples sold in a day × Number of days in a week

Amount of apples sold in 7 days = 157.5 × 7

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6 0
3 years ago
39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t
Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

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\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

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\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

4 0
2 years ago
Jacob consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Jacob's body
sasho [114]

Answer: 0.87400mg of caffeine.

Step-by-step explanation:

You have

N(t)=N0(e^−rt)(1)

as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,

N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)

Taking the last 2 parts of (2) to the power of 0.1t gives

e^−rt=0.2601^.1t . .(3)

This means that

N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)

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= 0.87400mg of caffeine.

6 0
3 years ago
The bread is on sale for $1.50 so Erica is also going to buy candy or gum. Which can she afford?
Alborosie
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