Answer:
ok do I have to do something? or just because?
Y intercept (x = 0)
4(0)+3y=12
3y = 12
y = 12/3
y = 4
X intercept (y = 0)
4x+3(0)=12
4x = 12
x = 12/4
x = 3
R/ The intercept with x is (3,0) and with y (0,4)
Consider the equation 
.
First, you can use the substitution 
, then 
and equation becomes 
. This equation is quadratic, so
.
Then you can factor this equation:
.
Use the made substitution again:
.
You have in each brackets the expression like 
that is equal to 
. Thus,
![x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=%20x%5E3%2B5%3D%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%20%2C%5C%5Cx%5E3%2B1%3D%28x%2B1%29%28x%5E2-x%2B1%29%20%20%20)
and the equation is
![(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0](https://tex.z-dn.net/?f=%20%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%28x%2B1%29%28x%5E2-x%2B1%29%3D0%20%20%20)
.
Here ![x_1=-\sqrt[3]{5} , x_2=-1](https://tex.z-dn.net/?f=%20x_1%3D-%5Csqrt%5B3%5D%7B5%7D%20%2C%20x_2%3D-1%20)
and you can sheck whether quadratic trinomials have real roots:
1. ![D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}](https://tex.z-dn.net/?f=%20D_1%3D%28-%5Csqrt%5B3%5D%7B5%7D%29%20%5E2-4%5Ccdot%20%5Csqrt%5B3%5D%7B25%7D%3D%5Csqrt%5B3%5D%7B25%7D%20-4%5Csqrt%5B3%5D%7B25%7D%20%3D-3%5Csqrt%5B3%5D%7B25%7D%20%20%3C0%20)
.
2. 
.
This means that quadratic trinomials don't have real roots.
Answer:
If you need complex roots, then
![x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2} ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}](https://tex.z-dn.net/?f=%20x_%7B3%2C4%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%5Cpm%20i%5Csqrt%7B3%5Csqrt%5B3%5D%7B25%7D%7D%7D%7B2%7D%20%20%20%2C%5C%5C%20%5C%5Cx_%7B5%2C6%7D%3D%5Cdfrac%7B1%5Cpm%20i%5Csqrt%7B3%7D%7D%7B2%7D%20%20%20%20)
.
$52,000 + 6% = $55,120
If this helped you, would you mind answering one of my recent questions? Thanks!
<span>Let us first find a ratio between the quantity of work done by Darnell and Julius. If Darnell does one part of the work, Julius does two parts of the work. That is, their work quantity ratio is 1:2. (Total 3 parts) In other words when Darnell does 1/3 of the work, Julius does 2/3 of the work.
When they work together, the work is completed in 4 hours. 4 hours work is the combined output of 1/3 by Darnell and 2/3 by Julius. If Julius was not there, Darnell would have to work for more than 4 hours.
We already know that Darnell does only 1/3 of a work during any given time. If the given time is 4 hours, how many one-thirds will Darnell require? To find the answer, divide the given number (4 hours in this case) by the given fraction( 1/3 in this case) To divide a number by a fraction, multiply the number by the reciprocal of the fraction. Thus it becomes 4 divided by 1/3 = 4 x 3/1 = 12.
(Another hint: At the rate of 1/3 of a work in one hour, Darnell will needs 3 hours to complete the given task. If the given work is 4 hours long, Darnell will take 4 x 3 hours, that is 12 hours.)</span>
