Answer:
9:20 is the answers for the question
Step-by-step explanation:
please tell me your
This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
Just keeping going with 16×-2=?×-2=?×-2 untill u get you your ninth nuber as well with tge 2 is a negative, so a a positive × a negative equal a negative and a negative × a negative equal
Answer:
(a) the size of each exterior angle 360/10=36
(b) the number of sides of the polygon. 10
Step-by-step explanation:
Each interior angle of a regular polygon is 4 times each exterior angle
∴sum of interior angles: (n-2)*180=4*360
n-2=8
n=10
(a) the size of each exterior angle 360/10=36
(b) the number of sides of the polygon. 10
