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mr Goodwill [35]
3 years ago
14

Pls help quick idk pls

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

The answer is 11 and 12

Step-by-step explanation:

you just find perfect squares

yulyashka [42]3 years ago
5 0

Answer:

11 and 12

Step-by-step explanation:

Using the following exact square roots

\sqrt{121} = 11

\sqrt{144} = 12

and

\sqrt{121} < \sqrt{134} < \sqrt{144}, that is

11 < \sqrt{134} < 12

You might be interested in
Find the height of the given pyramid.<br><br> 2.3m<br> 4.5m<br> 6m<br> 7m
Alex Ar [27]

Answer:

The height is 7 m.

Step-by-step explanation:

Volume = 1/3 * area of the base * height, so

28 = 1/3 * 3 * 4 * h

4h = 28

h = 7.

4 0
3 years ago
Figure ABCD is a kite. The area of ABCD is 48 square units. The length of line segment BD is 8 units. What is the length of AC?
astra-53 [7]
The area of a kite:
A = d1 * d2 / 2
d1 = BD = 8 units
48 = 8 * AC / 2
48 * 2 = 8 AC
96 = 8 AC
AC = 96 : 8 = 12
Answer: D ) 12 units
7 0
3 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
Hello there!
djyliett [7]

2. f(x) = x - 2x² - 5 + 10x

=-2x² + 8x - 5

f'(x)= -4x + 8

4. y = 100(45x - 30 - 3x³ + 2x²)

= 100(-3x³ + 2x² + 45x -30)

= -300x³ + 200x² + 4500x - 3000

y' = -900x² + 400x + 4500

5 0
3 years ago
6(m-1)=3(3m+5)<br> what does m=
love history [14]

Answer:

m = - 7

Step-by-step explanation:

Given

6(m - 1) = 3(3m + 5) ← distribute parenthesis on both sides

6m - 6 = 9m + 15 ( subtract 9m from both sides )

- 3m - 6 = 15 ( add 6 to both sides )

- 3m = 21 ( divide both sides by - 3 )

m = - 7

8 0
3 years ago
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