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3 years ago

Pls help quick idk pls

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

Answer:

The answer is 11 and 12

Step-by-step explanation:

you just find perfect squares

yulyashka [42]3 years ago

5 0

Answer:

11 and 12

Step-by-step explanation:

Using the following exact square roots

$\sqrt{121}$ = 11

$\sqrt{144}$ = 12

and

$\sqrt{121}$ < $\sqrt{134}$ < $\sqrt{144}$ , that is

11 < $\sqrt{134}$ < 12

You might be interested in

Find the height of the given pyramid. 2.3m 4.5m 6m 7m

Alex Ar [27]

Answer:

The height is 7 m.

Step-by-step explanation:

Volume = 1/3 * area of the base * height, so

28 = 1/3 * 3 * 4 * h

4h = 28

h = 7.

4 0

2 years ago

Figure ABCD is a kite. The area of ABCD is 48 square units. The length of line segment BD is 8 units. What is the length of AC?

astra-53 [7]

The area of a kite:
A = d1 * d2 / 2
d1 = BD = 8 units
48 = 8 * AC / 2
48 * 2 = 8 AC
96 = 8 AC
AC = 96 : 8 = 12
Answer: D ) 12 units

7 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Hello there!

djyliett [7]

2. f(x) = x - 2x² - 5 + 10x

=-2x² + 8x - 5

f'(x)= -4x + 8

4. y = 100(45x - 30 - 3x³ + 2x²)

= 100(-3x³ + 2x² + 45x -30)

= -300x³ + 200x² + 4500x - 3000

y' = -900x² + 400x + 4500

5 0

3 years ago

6(m-1)=3(3m+5) what does m=

love history [14]

Answer:

m = - 7

Step-by-step explanation:

Given

6(m - 1) = 3(3m + 5) ← distribute parenthesis on both sides

6m - 6 = 9m + 15 ( subtract 9m from both sides )

- 3m - 6 = 15 ( add 6 to both sides )

- 3m = 21 ( divide both sides by - 3 )

m = - 7

8 0

3 years ago