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mr Goodwill [35]
3 years ago
14

Pls help quick idk pls

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

The answer is 11 and 12

Step-by-step explanation:

you just find perfect squares

yulyashka [42]3 years ago
5 0

Answer:

11 and 12

Step-by-step explanation:

Using the following exact square roots

\sqrt{121} = 11

\sqrt{144} = 12

and

\sqrt{121} < \sqrt{134} < \sqrt{144}, that is

11 < \sqrt{134} < 12

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I NEED HELP ASAP I WILL MARK YOU BRAINLIEST
mojhsa [17]

Answer:

The angles are said to be linear if they are adjacent to each other after the intersection of the two lines. The sum of angles of a linear pair is always equal to 180°. Such angles are also known as supplementary angles. The adjacent angles are the angles which have a common vertex.

5 0
3 years ago
Hunter invested $750 in an account paying an interest rate of 6\tfrac{5}{8}6 8 5 ​ % compounded continuously. London invested $7
kompoz [17]

Answer: $ 55

Step-by-step explanation:

When interest is compounded continuously, the final amount will be

A=Pe^{rt}

When interest is compounded daily, the final amount will be

A=P(1+\dfrac{r}{365})^{365t}

, where P= Principal , r = rate of interest , t = time

For Hunter , P= $750, r = 6\dfrac{5}{8}\%=\dfrac{53}{8}\%=\dfrac{53}{800}=0.06625

t = 18 years

A=750e^{0.06625(18)}=\$2471.48

For London , P= $750, r = 6\dfrac{1}{2}\%=\dfrac{13}{2}\%=\neq \dfrac{13}{200}=0.065

t = 18 years

A=750(1+\dfrac{0.065}{365})^{18(365)}=\$2416.24

Difference = $ 2471.48 - $ 2416.24 =$ 55.24≈$ 55

Hence, Hunter would have $ 55 more than London in his account .

7 0
3 years ago
How will a high outlier in a data set affect the mean and median?
RUDIKE [14]

Answer:

B. distribution skewed to the right, mean pulled to the right, median not effected

Step-by-step explanation:

When a distribution is skewed to the right, it means that the data is positively skewed or has more positive numbers than negative numbers.

An outlier can affect the mean of a distribution since a high value outlier will make the mean be much higher than the median. In this case, since the distribution is positively skewed, a high outlier will pull the mean to the right (to higher positive values).

5 0
3 years ago
Let S be a sample space and E and F be events associated with S. Suppose that
Oksanka [162]

Answer:

a) P(E|F) = 0.5

b) P(F|E) = 0.167

c) P(E|F') = 0.625

d) P(E′|F′) = 0.375

Step-by-step explanation:

P(E) = 0.6

P(F) = 0.2

P(E n F) = 0.1

a) P(E|F) = Probability of E occurring, given F has already occurred. It is given mathematically as

P(E|F) = [P(E n F)]/P(F) = 0.1/0.2 = 0.5

b) P(F|E) = Probability of F occurring, given E has already occurred. It is given mathematically as

P(F|E) = [P(E n F)]/P(E) = 0.1/0.6 = 0.167

c) P(E|F′) = Probability of E occurring, given F did not occur. It is given mathematically as

P(E|F') = [P(E n F')]/P(F')

But P(F') = 1 - P(F) = 1 - 0.2 = 0.8

P(E n F') = P(E) - P(E n F) = 0.6 - 0.1 = 0.5

P(E|F') = 0.5/0.8 = 0.625

d) P(E′|F′) = [P(E' n F')]/P(F')

P(F') = 0.8, P(Universal set) = P(U) = 1

P(E' n F') = P(U) - [P(E n F') + P(E' n F) + P(E n F) = 1 - (0.5 + 0.1 + 0.1) = 0.3

P(E′|F′) = 0.3/0.8 = 0.375

7 0
3 years ago
The tires of an automobile have a diameter of 22 inches. If the wheels revolve ten times, how
Artyom0805 [142]
222inches I’m not shure but use photo math for the answer
5 0
3 years ago
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