Number of pounds of macadamia nuts is 8 pounds and number of pounds of almonds is 4 pounds.
<u>Step-by-step explanation:</u>
Step 1:
Given total pounds of mixture = 12 pounds, cost of macadamia nuts per pound = $9, cost of almonds per pound = $5.25, total cost of mixture per pound = $7.75.
Let number of pounds of macadamia nuts be x and number of pounds of almonds be 12-x.
Step 2:
Form an equation using the above information.
⇒ 9x + 5.25 (12-x) = 12 × 7.75
⇒ 9x + 63 - 5.25x = 93
⇒ 9x - 5.25x = 30
⇒ 3.75x = 30
⇒ x = 8
Number of macadamia nuts is 8 pounds.
Step 3:
Calculate number pounds of almonds
⇒ Number of pounds of almonds = 12 - x = 4 pounds.
In the first table, y = 4x. So y is proportional to x.
In the second table, y is not proportional to x.
In the third table, 2y = 3x. So, y is proportional to x.
2 triangles are formed
sum of angle measures of a triangle is 180*
sum of angle measures of a swuare is 360*
Answer:
is isosceles.
Step-by-step explanation:
Please have a look at the attached figure.
We are <u>given</u> the following things:


Let us try to find out
and
. After that we will compare them.
<u>Finding </u>
<u>:</u>
Side EG is a straight line so 
is sum of internal
and external 
<u>Finding </u>
<u>:</u>
<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.
i.e. external
= 

Comparing equations (1) and (2):
It can be clearly seen that:

The two angles of
are equal hence
is isosceles.
R * p = -37.8
Solve for either R or p.
R = -37.8/p
Now plug into R + p = 13.5
-37.8/p + p = 13.5
Solve for p.
After finding p, plug your p-value into either R + p or R*p to find R.
Take it from here.