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Setler [38]
3 years ago
14

What is 5634 divided by 5

Mathematics
2 answers:
mixas84 [53]3 years ago
4 0
5634 divided by 5 equals 1126.8
DIA [1.3K]3 years ago
3 0
The answer to 5634/5 is 1126.8
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SOMEONE MAKE A ENDING PARAGRAPH about someone rescuing me QUICK 40 POINTS!!!!
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Answer:

Although, my life can't end here, life has so much more to offer me. I collected the last of my strength to swim up to to surface where I can be released from the horrors of the deep waters. I swallowed gulps of the chlorine water and my eyes ached from being open for to long. I wrestled the clenching fists of the water that urged me to stay with them. I swam, and swam, swam, until I reached my hands out for help, and that's when I knew I made it. I could feel hands from above grasping me and helping me climb out of the bitter cold pool. I ran into my mother's arms, as a gush of relief spread through my body. The relief of staying in my mothers arm, that helped me forget the isolated pits of the dark waters.

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4 0
3 years ago
Express 14100000 in scientific notaion
S_A_V [24]
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8 0
3 years ago
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Evaluate the expression sv2 for s = 11 and v = 8<br> help please quick
statuscvo [17]
Is it SV squared? Or times 2
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2 years ago
What percent of 29.5 is 10.03
Alexxandr [17]
So if we take 29.5 to be the 100%, what is 10.03 in percentage?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;29.5&100\\&#10;10.03&p&#10;\end{array}\implies \cfrac{29.5}{10.03}=\cfrac{100}{p}\implies p=\cfrac{10.03\cdot 100}{29.5}
7 0
3 years ago
single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec
givi [52]

Answer:

\frac{1}{4}

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = \frac{3}{6} = \frac{1}{2}

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 =  \frac{3}{6} = \frac{1}{2}

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}

6 0
3 years ago
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