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3 years ago

Which set of vertices forms a parallelogram?

Mathematics

1 answer:

polet [3.4K]3 years ago

5 0

The answer to your question is C.

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Plz Help!!!!!!!!!!!!!!!!!!!!!!!!!

Novosadov [1.4K]

Answer:

line segments j' k' and m' n' do not intersect and are the same distance apart as jk and mn

Step-by-step explanation:

this is because if jk and mn are both moved to the left two units, the space between them does not change

4 0

3 years ago

erin needs 9.75 cups of flour to make 6 + 1/2 dozen cookies. how many cups of flour does erin need to make 1 dozen cookies

Hitman42 [59]

Erin needs 1.5 cups of flour to make 1 dozen cookies.

6 0

4 years ago

Find the value of x for the given value of y. y=9−7x; y=37

MrMuchimi

Answer:

For y=37, x= -4

Step-by-step explanation:

We have to find the value of x, when y=37 is the given value for the given equation

$y=9-7x$

Putting the value of y=37 in the equation to find the 'x'

$y=9-7x$

$37=9-7x\\7x=9-37\\7x=-28\\x=-4$

So, for the value of y=37, the value of $x=-4$

6 0

3 years ago

What is x(x+2) can someone show me how to do it please

yulyashka [42]

Answer:

x^2+2x

Step-by-step explanation: You would take x and multiply it by x and get X^2 then you would take x anm multiply it by 2 to get 2x. It is distributing

6 0

3 years ago

AUTOMOBILES The engine torque y (in foot-pounds) of one model of car is given by y = º3.75x2 + 23.2x + 38.8 where x is the speed

Scilla [17]

Answer:

Part 1) The engine speed that maximizes torque is $3,093 rev/min$

Part 2)The maximum torque is $74.683\ foot-pounds$

Step-by-step explanation:

<u><em>The correct equation is</em></u>

$y=-3.75x^{2}+23.2x+38.8$

This is the equation of a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the engine speed that maximizes torque

The y-coordinate of the vertex represent the maximum torque

Solve the quadratic equation by graphing

using a graphing tool

The vertex is the point (3.093,74.683)

see the attached figure

therefore

The engine speed that maximizes torque is

$3.093(1,000)=3,093 rev/min$ ---> because is in thousands of revolutions per minute

The maximum torque is

$74.683\ foot-pounds$

7 0

3 years ago