Which results only in a horizontal compression of y = StartFraction 1 Over x EndFraction by a factor of 6?
2 answers:
Answer:
Step-by-step explanation:
Recall that a horizontal compression in a factor "k" (with k>1, as in our case) of a function's graph is obtained when we multiply the "x" variable by "k".
In our case, k = 6, and therefore, the function would be compressed by a factor of 6 by multiplying all appearances of the variable "x" in the function, by the factor "6". That is:
Notice as well, that no negative factor should be included, since there is no reflection required about any of the axes.
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Transforming equation systems into matrix form is fairly simple:
each column represents a variable, and each line represents an equation.
So in the first column, the NUMBERS MULTIPLYING by the X variables are put, in the second one the ones multiplying by Y, etc. The constants go after the vertical line, the last column
so we have:
So in a matrix, it will be the one on the picture
each column represents a variable, and each line represents an equation.
So in the first column, the NUMBERS MULTIPLYING by the X variables are put, in the second one the ones multiplying by Y, etc. The constants go after the vertical line, the last column
so we have:
So in a matrix, it will be the one on the picture
Answer:
5115
Step-by-step explanation:
First of all, we need to assume there is a typo involved, and that the expression is supposed to be ...
The values being summed look a lot like the general term of a geometric sequence:
The exponents in the sum range from 1 to 10, so the values being summed range from 5/2 to 5/1024. In order for that to be the case with our general term, for r = 1/2, we must have a1 = 5/2 as we let n range from 1 to 10.
The sum of the terms of the geometric sequence is ...
The numerator of the fraction is ...
x = 5115
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<em>Caveat</em>
If we have misinterpreted the intent of the problem statement, the answer will be different.