Please help ;(
1 answer:
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Answer:
The margin of error for this estimate is of 14.79 yards per game.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
T interval
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.093
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.
This means that
What is the margin of error for this estimate?
The margin of error for this estimate is of 14.79 yards per game.
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
let x = number of miles per hour
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour
You can set up a proportion:
let x = number of miles per hour
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour