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sveticcg [70]
3 years ago
6

Find all the critical points of h(x) = x^3 − 3x^4 and categorize them as local

Mathematics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

0 is an inflection point

1/4 is a local maximum.

Step-by-step explanation:

To begin with you find the first derivative of the function and get that

h'(x) = 3x^2 - 12x^3

to find the critical points you equal the first derivative to 0  and get that

3x^2 - 12x^3 = 0, x =  0,1/4

To find if they are maximums or local minimums you use the second derivative.

h''(x) = 6x-36x^2

since h''(0) = 0 is neither an inflection point, and since h''(1/4) = -3/4 then 1/4 is a maximum.

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Solve the equations.<br> a. (x − 2)^2 = 9<br> b. 3(x − 2)^2 = 9<br> c. 6 = 24(x + 1)^2
seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

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Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

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x = 5 and;

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b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

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c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

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x + 80 = 80

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3 years ago
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