You should draw a picture to visualize the problem easier.
The circumference of inner circle = 44 ft
That means the radius of the inner circle:
2*pi*r = 44
r = 44/(2pi) = 22/pi
Using the picture you hopefully drew, we see that the radius of the outer circle:
22/pi + 2
To figure out the circumference of the outer circle:
2pi*(22/pi + 2) = 44 + 4pi
So how much bigger is the the circumference of the outer circle than the inner circle?
44 + 4pi - 44 = 4pi
It is 4pi bigger or 4 * (3.14) = 12.56 feet
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Take the picture clearly because I can’t read nothing
The answer to which is bigger is -5 because it is closer to zero