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Dennis_Churaev [7]
3 years ago
14

Rewrite the following mixed number as a decimal. 8 1/100

Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0

Answer:

8.01

Step-by-step explanation:

8\frac{1}{100} is the same as \frac{801}{100}

Divide:

801 ÷ 100 = 8.01

damaskus [11]3 years ago
6 0

Answer:

8.01

Step-by-step explanation:

Because 8 is a whole number, it has to be in the ones place or higher. In this case, 8 is a 1-digit number, so it is in the ones place. Second, 1/100 is the same as 0.01 because 0.1 is 1 tenth and then if the decimal point is moved one step to the right, the place value is moved to the right one time as well. So, if 8 and 0.01 are added, the final answer is 8.01.

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Which equation has no solution?
Alex

Answer:

  • B. the absolute value of 5 minus 3 x equals negative 8

Step-by-step explanation:

The absolute value is never negative as per definition.

  • A. |2x - 1| = 0, has solution
  • B. |5 - 3x| = - 8, no solution
  • C. |-x - 3| = 5, has solution
  • D. |-x + 9| = 0, has solution

Correct choice is B

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3 years ago
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If a snail can move 3\10 of meter every 1\12 hour, what is the speed of the snail, meters per hour
alekssr [168]
The answer is 3/5 meters per hour
4 0
3 years ago
X in 5xy = 10 to solve the system<br> below.<br> x = 25 - y<br> 5x + y =10
lora16 [44]

Answer:

Step-by-step explanation:

there are two ways to solve systems of equations,  elimination or substitution, this looks like elimination would work quickly

x= 25 -y

x + y = 25   (eq 1)

5x + y = 10  (eq 2)

subtract 2 from 1

x + y = 25  

-(5x + y = 10)

-4x + 0y = 15

-4x = 15

x = - 15/4

now plug in x into either starting equations and solve for y

-15/4 + y = 25

y = 25 + 15/4

y = 100/4 + 15 /4

y = 115 /4

y = 28 3/4

we have solved it :)

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3 years ago
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vlabodo [156]

Answer:

x = 5 ; z = 70

Step-by-step explanation:

Vertical angles have the same degree measure

(13x + 45) = 110

13x + 45 = 110

      -45     -45

13x = 65

/13     /13

x = 5

Complementary angles add up to 180°

110 + z = 180

-110         -110

z = 70

8 0
3 years ago
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A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t
denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

\widehat{Y}=Y_1+Y_2+...+Y_{200}

=200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

 S=\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486

Then, the standard error of \widehat{Y} is

\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:=83.785

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45

The sample ratio is

r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}=0.1 , this is also the estimate of the population ratio R=\frac{\overline{Y}}{\overline{X}} .

Therefore, the estimated total weight of grain in the population using ratio estimator is

\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\, lbs

4) The variance of the ratio estimator is

var(r)=\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1}   , where \mu_x=8800/200=44lbs

=\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005

Hence, the standard error of the estimate of the total population is

\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:=21.556

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]

8 0
4 years ago
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