Perimeter- 28ft
N=11
Hey, do you remember the one I explained earlier? This one is really close to that. To find the area, you do the length times the width. This means
N*3
You already know the area so now, it’s
N*3=33
Divide both sides by 3 to get N alone and you get
N=11
Then, you have to find the perimeter by adding all of the sides. This means 3+3+11+11
This equals 28
Answer:
If we have a cone-shape candle with r=2 cm and h=3 cm, then the amount of paper needed is 18.84 cm^2 and the amount of plastic needed is 12.56 cm^2.
Step-by-step explanation:
<em>The question is incomplete: no numerical values for the dimensions of the cone are given.</em>
<em />
A right cone is defined by the radius r of the base and the height h.
The base area is the area of a circle with radius r:
![A_b=\pi r^2](https://tex.z-dn.net/?f=A_b%3D%5Cpi%20r%5E2)
The lateral area is calculated as:
![A_l=\pi \cdot r\cdot l](https://tex.z-dn.net/?f=A_l%3D%5Cpi%20%5Ccdot%20r%5Ccdot%20%20l)
As the values for r and h are not given, we will use an example with r=2 and h=3.
Then, the amount of paper needed is:
![A_l=\pi \cdot r\cdot l=3.14\cdot (2\,cm)\cdot (3\, cm)=18.84\,cm^2](https://tex.z-dn.net/?f=A_l%3D%5Cpi%20%5Ccdot%20r%5Ccdot%20%20l%3D3.14%5Ccdot%20%282%5C%2Ccm%29%5Ccdot%20%283%5C%2C%20cm%29%3D18.84%5C%2Ccm%5E2)
The amount of plastic needed is:
![A_b=\pi r^2=3.14\cdot (2\,cm)^2=3.14\cdot 4\,cm^2=12.56\,cm^2](https://tex.z-dn.net/?f=A_b%3D%5Cpi%20r%5E2%3D3.14%5Ccdot%20%282%5C%2Ccm%29%5E2%3D3.14%5Ccdot%204%5C%2Ccm%5E2%3D12.56%5C%2Ccm%5E2)
2, 222 bc if 200 is in the hundreds then all the digits are the same so therefore it's 2,222
18% em forma decimal é 0.18.
Porque isto é um aumento de valor, adicionamos a percentagem original aos 18%.
1.18 é o multiplicador que necessitamos.
Agora:
![900,000*1.18=1,062,000](https://tex.z-dn.net/?f=900%2C000%2A1.18%3D1%2C062%2C000)
A resposta é R$1,062,000.