To rewrite this expression is first you must analyze first the equations and then proceed the the cancellations of values that are the same or having the same variables and the answer for this question is C tan x
Two-fifths time a plus a over 2 equals a minus 2 will be a=20
<u>Step-by-step explanation:</u>
We have to find a, by first writing the verbal expression into an arithmetic form as,
Two fifths times a = (2/5)a
a over 2 = a/2
a minus 2 = a-2
(2/5)a + (a/2) = a-2
We have to take LCM on LHS as 10.
(2×2 /5×2)a + (a×5 /2×5) = a-2
(4a/10) + (5a/10) = a-2
Moving 10 to the other side, we will get,
4a+ 5a = 10(a-2)
9a = 10a -20
Grouping terms we will get,
10a - 9a = 20
a = 20
<span>The differentiable functions are one for which there is a departure line at each position on the graph. The digression line to the graph y = f (x) at the point (a, f (a)) is given by the equation. Moreover the other line (at least near (a, f (a))), the function La is the best linear and find the best linear guess to the function f (x) = sqrt (x) near 100.</span>