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densk [106]
3 years ago
11

I need help pleaseee…

Mathematics
2 answers:
Nataly [62]3 years ago
8 0
B. Comparative

Hope this helps;)
frez [133]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Find a decimal that meets all the following criteria. Rounds to 35 when rounded to the nearest whole number. Rounds to 34.6 when
vaieri [72.5K]

I believe you could say the answer would be 34.651

The last digit could be any number from 1 to 4, since going to 5 would make it 34.66

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4 years ago
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Find the value of x.<br> Find the value of y.<br> Y<br> 61<br> X
mel-nik [20]

Answer:

61=x ( vertical opposite angle)

61=y (corresponding angle)

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3 years ago
Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy
Margaret [11]

Answer:

Part 1) The exact solutions are

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})   and  (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

y=x^{2} +3x ----> equation A

y=2x+5 ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +x-5=0  

so

a=1\\b=1\\c=-5

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}

x=\frac{-1\pm\sqrt{21}} {2}

so

The solutions are

x_1=\frac{-1+\sqrt{21}} {2}

x_2=\frac{-1-\sqrt{21}} {2}

<em>Find the values of y</em>

<em>First solution</em>

For x_1=\frac{-1+\sqrt{21}} {2}

y=2(\frac{-1+\sqrt{21}} {2})+5

y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}

The first solution is the point (\frac{-1+\sqrt{21}} {2},4+\sqrt{21})

<em>Second solution</em>

For x_2=\frac{-1-\sqrt{21}} {2}

y=2(\frac{-1-\sqrt{21}} {2})+5

y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}

The second solution is the point (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Round to the nearest hundredth

<em>First solution </em>

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21}) -----> (1.79,8.58)

(\frac{-1-\sqrt{21}} {2},4-\sqrt{21}) -----> (-2.79,-0.58)

see the attached figure to better understand the problem

6 0
4 years ago
What number can go into 21 and 27
astra-53 [7]

3 only

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3 years ago
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A 16-digit binary pattern converts to a ____ digit hexadecimal value.
Doss [256]

Solution -

In order to convert a binary number to hexadecimal ,we need to chunk the binary number into groups of 4 digits, adding 0 if necessary.

As the given number number is a 16 digit binary number, so when chunk in 4 digit groups, it will form 4 groups. Each group will represent a single digit in hexadecimal code.  

So, a 16-digit binary pattern converts to a 4 digit hexadecimal value.

7 0
3 years ago
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