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3 years ago

Anyone know the answers to 1, 2, 3, 4, 5

Mathematics

1 answer:

muminat3 years ago

6 0

Answer:

1. C. 1/4(4) + 1/4(9) (A, 1/4(13), is essentially C simplified (without figuring it out).)

2. G - -4

3. A - -4(-5) + (-4)x

4. J - 1/6x + 1/6y

5. A - 60(10 + 2)

Step-by-step explanation:

1/4(4 + 9) We can distribute 1/4 into 4 and 9.

1/4(4) + 1/4(9) Now while we have our answer, this can be further simplified.

1/4(13) What's on the left is the simplified 2-term equation.

So really, either C or A will be the answer. But due to the format of #3, I put C as my answer. B & D were out because there wasn't any extra multiplication.

-2/5(15 - 5) Subtract 5 from 15 to get 10.

-2/5(10) Multiply -2/5 by 10 to get -20/5

-20/5 Divide -20 by 5 to get -4.

-4, so G is the answer. This was negative, so H & J were out to begin with. F was out as soon as I solved the problem.

-4(-5 + x) Distribute -4 into -5 + x.

-4(-5) + (-4)x, so A is the answer. Don't get tricked! B may look right, but there should be a negative sign in front of the 5, hence why it's incorrect.

1/6(x + y) Distribute 1/6 into x + y.

1/6x + 1/6y, so J is the answer. F & G are already out because you don't multiply the variables by each other. H is also out because there wasn't any multiplication involved other than x + y being multiplied by 1/6.

Only 60(10 + 2) would have worked, so A is the answer. The tickets would have cost 720 dollars (600 + 120). B would have equated to 624 (24 + 600), C would have been 132 (6 * 22), and D would have been 600. (10 * 60).

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Answer:

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Step-by-step explanation:

Step one:

given data

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<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

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More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

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