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Rom4ik [11]
3 years ago
15

If 10% of all machines become worthless every year (they depreciate, in other words), then how many machines will become worthle

ss in these three countries this year? (This question reminds you that "More machines mean more machines wearing out.")
Country A: K = 100 machines;
Country B: K = 10,000 machines;
Country C K = 1,000,000 machines
Mathematics
1 answer:
nikklg [1K]3 years ago
5 0

Answer: Country A - 10machines

Country A - 1,000machines

Country A - 10,000machine

step-by-step explanation:

Since 10℅ of all machines becomes worthless every year, let's look at each country.

If 100 machines are all the machines in country A, then 10% of all the machines in country A (i.e 100 machines) will be 10% of 100 = 10 machines.

Similarly for country B, it will be equivalent to 10% of 10000, which is equal to 1,000machines.

Same goes for country C i.e 10% of 1000000 = 10,000machines are worthless.

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