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4 years ago

What is the equation of a horizontal line that passes through the point (-4, -5)?

Mathematics

1 answer:

ZanzabumX [31]4 years ago

3 0

Answer: y=-5

Step-by-step explanation:

A horizontal line appears on the graph if it goes through the y-axis. Knowing this, the coordinate tells us that the y-coordinate is -5. This tells us that the equation of the line is y=-5.

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Use the formula F = 1.8C + 32 to convert -10C into Fahrenheit

photoshop1234 [79]

Well since the value of C has been given to you, plug it into the equation.

F = 1.8(10) + 32
F = 18 +32
F = 50

The temperature in Fahrenheit would be 50 degrees.

4 0

4 years ago

Read 2 more answers

-3√x-6- y²<br> if x= 55 and y=-4

Law Incorporation [45]

Answer:

=−44.248595

Step-by-step explanation:

Evaluate for x=55,y=4

−3√55−6−42

4 0

3 years ago

Graciella divided her grapes equally among 6 friends. If each friend received 16 grapes, how many grapes did Graciella have? let

storchak [24]

Answer:

If between 6 friends, each got 16 by dividing. Doing multiplication will give us our variable. 16(6)=g

Step-by-step explanation:

16 g per friend

6 friends total

16 times 6= total g

16(6)=96

g=96

5 0

4 years ago

Read 3 more answers

I forgot how to do this.... can somebody help?

slamgirl [31]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}

$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D = -3

$\bf f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}\implies f(x)={{ -2}}(\mathbb{R})^{{{ 1}}x-{{ 3}}}-{{3}}\\\\\\ f(x)={{ -2}}(3)^{{{ }}x-{{ 3}}}-{{3}}$

3 0

4 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!

Lelechka [254]

x=4.75

6×4.75=28.5

15×4.75-12=59.25

19×4.75+2=92.25

28.5+59.25+92.25=180

m<MNI= 92.25

I think this is right. I hope that it was helpful:)

8 0

3 years ago