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4 years ago

8

Reduce to lowest terms. 3m^2-3n^2/6m-6n A) -m-n/2 B) m-n/2 C) m+n/2

2 answers:

USPshnik [31]4 years ago

6 0

Answer:

C. m+n/2

Step-by-step explanation:

Factor out the 3 in the numerator and apply the difference of squares, factor out the 6 in the denominator, and reduce where applicable. It'll all cone out to look like option C.

dezoksy [38]4 years ago

6 0

Answer:

C)

$\frac{m + n}{2}$

Step-by-step explanation:

$\frac{3{m}^{2} - 3 {n}^{2} }{6m - 6n } = \frac{3( {m}^{2} - {n}^{2}) }{3(2m - 2n)} \\ = \frac{ {m}^{2} - {n}^{2} }{2m - 2n} \\ = \frac{(m - n)(m + n)}{2(m - n)} \\ = \frac{m + n}{2}$

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andrew-mc [135]

Answer:

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Step-by-step explanation:

In linear equations, both variables x and y must have the exponent of 1 (i.e. they cannot have a small number at the top-right). And they cannot be in the exponents (i.e. cannot be the small number at the top-right).

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3 years ago

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Artist 52 [7]

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3 years ago

If θ is an angle in standard position that terminates in Quadrant IV such that cosθ = 3/5, then cosθ/2 = _____. -

Sveta_85 [38]

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Step-by-step explanation:

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3 years ago

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2 years ago

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Komok [63]

Answer:

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Step-by-step explanation:

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3 years ago