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2 years ago

Solve the equation: -6p + 14 and 3p - 2

Mathematics

1 answer:

sleet_krkn [62]2 years ago

5 0

Answer:

p = 16/9

Step-by-step explanation:

$-6p+14=3p-2\qquad\text{subtract 14 from both sides}\\\\-6p=3p-16\qquad\text{subtract 3p from both sides}\\\\-9p=-16\qquad\text{divide both sides by (-9)}\\\\\boxed{p=\dfrac{16}{9}\to p=1\dfrac{7}{9}}$

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46. Order these numbers from least to greatest: 1/2, 0.4, 1/3, 1/5

e-lub [12.9K]

Answer:

1/5, 1/3, 0.4, 1/2

Step-by-step explanation:

1/5 = 0.2

1/3 = 0.33

1/2 = 0.5

4 0

2 years ago

Complete the following proof. Prove: In an isosceles triangle, two medians are equal.

Paraphin [41]

Answer:

Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)

x coordinate of point c = a

N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)

M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)

MA = √(3a / 2 - 0)² + b / 2 - 0)²

= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4

NB = √(a / 2 - 2a)² + (b / 2 - 0 )²

= √( a / 2 - 4a / 2)² + (b / 2 - 0)²

= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4

Step-by-step explanation:

I tried my best hope its correct :0

8 0

2 years ago

List all the factors of 16

Olenka [21]

Answer:

There are 5 factors of 16, which are 1, 2, 4, 8, and 16.

5 0

2 years ago

Read 2 more answers

In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311

Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

$Z_{1-\alpha /2}= Z_{0.975}= 1.965$

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

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3 years ago

What is the initial value in the exponential equation below? y = = 4000(1.05)*

Svet_ta [14]

Answer:

$y = 4000$ (when x = 0)