Answer:
309 feet
Step-by-step explanation:
given that the height can be represented by a quadratic equation, we can say that the general form of the equation will look something like this:
h(x) = Ax² + Bx + C
we know that at the starting point of the launch that time = 0 (i.e x = 0) and hence h (x) = 0, if we substitute this into our equation, we can find the value for C
h(0) = A(0)² + B(0) + C = 0
C = 0
Hence the equation becomes
h(x) = Ax² + Bx
Given when x = 1, h(1) = 121,
121 = A(1)² + B(1)
A + B = 121 ------> eq 1
Given when x = 2, h(2) = 224,
224 = A(2)² + B(2)
4A + 2B = 224 (divide both sides by 2)
2A + B = 112------> eq 2
Solving the system of equations which comprise eq 1 and eq 2 using your favorite method, we end up with A = -9 and B = 130
our equation becomes:
h(x) = -9x² + 130x
when x = 3
h(3) = -9(3)² + 130(3) = 309 feet
Answer:
x=2/5
Step-by-step explanation:
Answer:
28 km per hour
Step-by-step explanation:
First determine the amount of time that the trip took
17:55 - 17:40 = :15 or 15 minutes
We need the time in hours
15 minutes * 1 hour/ 60 minutes = 15/60 hours = 1/4 hours
To determine speed, take distance and divide by time
7 km ÷( 1/4 hours)
Copy dot flip
7 * 4/1
28 km per hour
Answer:
{-7, 2, 8}
Step-by-step explanation:
We see that the domain is limited to three x-values: -3, 0 and 2. To find the range (which is the set of all y-values) we just need to plug-in these x-values and find the corresponding y-values.
So our equation is:
y = 3x + 2
Then we substitute for the x-values:
y = 3(-3) + 2
y = -9 + 2
y = -7
y = 3(0) + 2
y = 0 + 2
y = 2
y = 3(2) + 2
y = 6 + 2
y = 8
So our range would be {-7, 2, 8}.
