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chubhunter [2.5K]
3 years ago
13

I told you people that i would be sending out a series of problems todayy!!

Mathematics
1 answer:
qwelly [4]3 years ago
3 0
Each student would need to raise $27.56
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Which of the following points lies in the solution set of the inequality y > 3x +10?
shepuryov [24]

Since 3 is greater than -3, hence (-1, 3) lie in the solution set. Option C is correct

In order to determine the points that lie in the solution set of the inequality y > 3x +10, we will substitute the x-coordinate and see if <u>y is greater than the result.</u>

<u />

For the coordinate point (1, 10)

y > 3(1) +10

y > 13

Since 10 is not greater than 13, hence (1,10) does not lie in the solution set.

For the coordinate point (4, 20)

y > 3(4) +10

y > 22

Since 20 is not greater than 22, hence (4,20) does not lie in the solution set.

For the coordinate point (-1, 3)

y > 3(-1) +10

y > -7

Since 3 is greater than -3, hence (-1, 3) lie in the solution set.

Learn  more on inequality here: brainly.com/question/24372553

7 0
3 years ago
HELPPP PLEASEEEE
Kryger [21]

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

3 0
2 years ago
The plan for the Thorne’s backyard play area, shaped like a trapezoid, is shown. The area of the play area is 286.56 square feet
lorasvet [3.4K]

The length of material needed for the border is the perimeter of the backyard play area

<h3>How to calculate the length of material needed </h3>

The area of the play area is given as:

Area = 286.56

The area of a trapezoid is calculated using:

Area = 0.5 * (L1 + L2) * H

Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.

The given parameter is not enough to solve the length of material needed.

So, we make use of the following assumed values.

Assume that the parallel sides are: 25 feet and 31 feet long, respectively.

While the other sides are 10.2 feet and 8.2 feet

The length of material needed would be the sum of the above lengths.

So, we have:

Length = 25 + 31 + 10.2 + 8.2

Length = 74.4

Using the assumed values, the length of material needed for the border is 74.4 feet

Read more about perimeters at:

brainly.com/question/17297081

6 0
2 years ago
I don’t understand how this question
Vladimir79 [104]

Answer:

<u>x = √51</u>

Step-by-step explanation:

The given figure is a <u>right triangle</u>.

<u>Using the Pythagorean Theorem to find x</u>

  • (Altitude 1)² + (Altitude 2)² = (Hypotenuse)²
  • (7)² + x² = (10)²
  • 49 + x² = 100
  • x² = 51
  • <u>x = √51</u>
4 0
2 years ago
What is the equation of a line perpendicular to:
Nataly [62]

Step-by-step explanation:

"perpendicular" means it creates a right angle (90°) with the original line.

a key element is the slope (the incline) of the line.

it is the factor of x (here 1/4 for the original line) and is defined as the ratio of "y coordinate change / x coordinate change" when going from one point on the line to another.

the given slope of 1/4 means that for every increase in x by 4 units y increases by 1 unit.

now if you want to draw a few random lines, and then draw lines that cross them with a right angle, you will see very quickly the relationship of the slopes of the crossing lines :

for the slope of the perpendicular line x and y of the original slope trade places (the ratio turns "upside-down") and the sign of the slope flips (if the original line goes up, then the perpendicular line goes down and vice versa. so + turns into -, and - into +).

so, our original slope 1/4 turns into -4/1 = -4.

we still have infinite possibilities to draw such a perpendicular line (more up or more down on the coordinate grid).

to finally "nail" one particular line we need to use the given point and solve for the y-intercept.

the general slope-intercept form is

y = ax + b

a is the slope, b is the y-intercept (the y value for x = 0).

so, using the slope (-4) and the point (2, 5) we have

5 = -4×2 + b = -8 + b

13 = b

so, the full equation is

y = -4x + 13

7 0
2 years ago
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