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chubhunter [2.5K]
2 years ago
13

I told you people that i would be sending out a series of problems todayy!!

Mathematics
1 answer:
qwelly [4]2 years ago
3 0
Each student would need to raise $27.56
You might be interested in
Y=8-2x when x=8 the value of y
Lera25 [3.4K]

Answer:

-8

Step-by-step explanation:

Given that x and y are two variables.  they are related by the function

y =8-2x

Since x and y are related, given one value we can find the other using this equation.

In our question, given that x =8

Substitute x value in the equation

y = 8-2x

y =8-2(8) = -8

Hence answer is -8:


Verify:  We verify by putting -8 for y and check whether x =8

-8=8-2x

Or 2x = 16

x =8

Verified

8 0
3 years ago
Read 2 more answers
Factorize 16x - 6 and show correct and full working.
Vlad1618 [11]
\left[x \right] = \left[ \frac{3}{8}\right][x]=[​8​​3​​] totally answer
8 0
2 years ago
Select True or False for each statement. 1 4 9 + 7 6 9 is equal to 8 1 9 . 5 5 6 + 3 3 6 is equal to 8 2 6 . 4 5 8 − 2 4 8 is eq
Elena L [17]

Answer:

(1) False

(2) False

(3). False

(4) False

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

(1). Given,  149 + 769 = 819

By calculating 149 + 769 = 918  

Hence, False

(2). Given,  556 + 336 = 826

By calculating 556 + 336 = 892  

Hence, False

(3). Given,  458 - 248 = 238

By calculating 458 - 248 = 210  

Hence, False

(4). Given,  658 - 228 = 438

By calculating 658 - 228 = 430  

Hence, False

4 0
3 years ago
Three of the angles of a polygon are
zmey [24]

Answer:

three angles of a polygon are each 105.5,the sum of the angles in the polygon is 2520. find each of the other angles if they are equal to each other. For a polygon with n sides and n angles, the sum of the measures of all the interior angles equals (n-2)180 degrees. 16-3=13

6 0
3 years ago
Can someone make 3 or more equations with 2 variables on both sides, in a fraction, integer, and decimal form?
Goryan [66]

hi it could be 3x+2=180 , 3/4x+19=189, 3.4x+12=100

8 0
3 years ago
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