Ask question

Ask question

All categories

3 years ago

12

What are the solutions for x when y is equal to 0 in the following quadratic function? A. x = 3 or x = 4 B. x = –3 or x = 4 C. x

= 3 or x = –4 D. x = –3 or x = –4

1 answer:

AlladinOne [14]3 years ago

6 0

ans B. x = -3 or x =4

You might be interested in

X/a+x/b=1<br>make x the subject of the formular

monitta

Answer:

x = $\frac{ab}{b+a}$

Step-by-step explanation:

Given

$\frac{x}{a}$ + $\frac{x}{b}$ = 1

Multiply through by ab to clear the fractions

bx + ax = ab ← factor out x from each term on the left side

x(b + a) = ab ← divide both sides by (b + a)

x = $\frac{ab}{b+a}$

8 0

3 years ago

Are two equilateral triangles always similar

sukhopar [10]

Yes because all equilateral triangles have equal angles and side lengths so they are all similar. hope i helped -J

4 0

3 years ago

True or false: in order to fill the following box, you would need to fill in 2 unit cubes in length, 2 unit cubes in width, and

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

True

7 0

3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago

The half-life of a certain substance is 20 years. How much of a 100 gram sample will be left after 20 years?

cluponka [151]

$\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &100\\ t=\textit{elapsed time}\dotfill &20\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=100\left( \frac{1}{2} \right)^{\frac{20}{20}}\implies A=100\left( \frac{1}{2} \right)^1\implies A=50$

5 0

3 years ago

Read 2 more answers