Question

1.If a 40 kg person is accelerating at 10 m/s2, then the force acting on him or her is 400 N

Answer 1

In all of the questions, we apply Newton's second law that:
Force = mass x acceleration
1) A. True

2) C, 120 N; F = 60 x 2 = 120N

3) A, 6 m/s²; a = F/m = 180/30 = 6

4) A; F = ma → m = F/a

Answer 2

Answer: 1) The given statement is true.

2 .The correct answer is option C.

3.The correct answer is option A.

4.The correct answer is option A.

Explanation:

1. Mass of the person = m = 40 kg

Rate of acceleration of person = a = $10 m/s^2$

Force on the person =  $F=mass\times acceleration = 40 kg\times 10 m/s^2=400 N$

True, the force acting on him or her is 400 N.

2.Mass of an object ,m= 60 kg

Rate of acceleration of an object ,a= $a=2.0 m/s^2$

Force required:

$F=m\times a=60 kgtimes 2.0 m/s^2=120.0 N$

Hence, the correct answer is option C.

3. Mass of an object ,m= 30 kg

Force applied ,F = 180 N

Let rate of the acceleration be = a

$F=m\times a$

$a=\frac{180 N}{30 Kg}=6.0 m/s^2$

Hence, the correct answer is option A.

4. If we know the force acting on an object along with acceleration of an object.

From the formula: F= ma

Mass can be determined by:

$m=\frac{F}{a}$

Hence, the correct answer is option A.