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3 years ago

5

b. Comparing and Contrasting Compare the change in atmospheric pressure with elevation to the change in water pressure with dept

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1 answer:

olasank [31]3 years ago

4 0

Answer:

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Explanation:

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Appliances connected so that they form a single pathway for

Serga [27]

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Appliances connected so that they form a single pathway for charges to flow are connected in a(n)

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3 years ago

Which characteristic best identifies a pure substance?

RSB [31]

<span> A pure substance is an material which contains atoms of only one kind.
It has fixed physical and chemical properties such as boiling point, melting point, valency, density and more.</span>

8 0

3 years ago

Increase 90 in the ratio 6 : 5

Jobisdone [24]

Answer:

<em>108</em>

Explanation:

<u>Proportions </u>

Two quantities are proportional when one of them can be obtained by multiplying or dividing the other by a constant value. For example, knowing the price of one pencil as p, we can know the cost of purchasing X pencils as C=p.X

We are required to increase 90 by the ratio 6:5. The new value will be proportional to the original because we'll compute the product of

$\displaystyle 90\ \frac{6}{5}=108$

So the new value is 108

3 0

3 years ago

g power output of 87 W. At what distance will the decibel reading be 120 dB, which is noise level of a loud indoor rock concert

Kazeer [188]

Given that,

Output power = 87 W

Decibel reading = 120 dB

We need to calculate the intensity of sound

Using formula of intensity of sound

$dB=10\log(\dfrac{I}{I_{0}})$

Put the value into the formula

$120=10\log(\dfrac{I}{1\times10^{-12}})$

$12=log(\dfrac{I}{1\times10^{-12}})$

$10^{12}=\dfrac{I}{1\times10^{-12}}$

$I=10^{12}\times1\times10^{-12}$

$I=1\ W/m^2$

We need to calculate the distance

Using relation of power out[ut and intensity

$I=\dfrac{P}{4\pi r^2}$

Put the value into the formula

$1=\dfrac{87}{4\pi r^2}$

$r=\sqrt{\dfrac{87}{4\pi}}$

$r=2.63\ m$

Hence, The distance is 2.63 m

7 0

3 years ago

Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch ve

Oksana_A [137]

Answer:

gs = 0.6 m/s^2

Explanation:

Given data:

velocity = 12 m/s

height s = 12t -(1/2) g_s t^2

Given velocity is the derivatives of height

$v(t) = \frac{d}{dt} s(t)$

$= \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)$

$= 12 - g_s t$

when velocity tend to 0 , maximum height is reached

$v(t) = 12 - g_s t$

$0 = 12 - g_s t$

$g_s = \frac{12}{t}$

at t = 20 sec ball reached the max height, so

$g_s = \frac{12}{20} = 0.6 m/s^2$

5 0

3 years ago