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lilavasa [31]
3 years ago
14

Albert uses as his unit of length (for walking to visit his neighbors or plowing his fields) the albert (a), the distance albert

can throw a small rock. one albert is 88 meters. how many square alberts is equal to one acre? (1 acre = 43,560 ft2 = 4050 m2)
Physics
1 answer:
True [87]3 years ago
7 0

To solve this problem, we know that:

1 Albert = 88 meters

1 A = 88 m

The first thing we have to do is to square both sides of the equation:

(1 A)^2 = (88 m)^2

1 A^2 = 7,744 m^2

<span>Since it is given that 1 acre = 4,050 m^2, so to reach that value, 1st let us divide both sides by 7,744:</span>

1 A^2 / 7,744 = 7,744 m^2 / 7,744

(1 / 7,744) A^2 = 1 m^2

Then we multiply both sides by 4,050.

(4050 / 7744) A^2 = 4050 m^2

0.523 A^2 = 4050 m^2

<span>Therefore 1 acre is equivalent to about 0.52 square alberts.</span>

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PtichkaEL [24]

Answer:

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Explanation:

Given;

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acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

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P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

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Total resultant velocity=5.11-3.27=1.84m/s

  • m_1=61.4kg
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  • v_1=1.84m/s
  • v_2=?

\\ \sf\longmapsto ∆P=P

\\ \sf\longmapsto m_1v_1=m_2v_2

\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}

\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}

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\\ \sf\longmapsto v_2\approx 1.3m/s

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Answer/solution:

Given :

Mass =5kg

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Q=m×C×ΔT

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Answer: 5 \frac{g}{cm^{3}}

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V is the volume of the cube

Now, the volume of a cube is equal to the length L of its edge to the power of 3:

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If we know L=9 cm, the volume of this cube is:

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Substituting (3) in (1):

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