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ollegr [7]
3 years ago
8

At noon a tank contained 10 cm of water. After several hours, it contained 7 cm of water. What is the percent decrease of water

in the tank.
Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

30%

Step-by-step explanation:

Because it lost 3 cm out of 10 which is 30%.

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____ x 11 = 13 x (8 x 11)
Ann [662]

Answer:

(13 x 8) x 11 = 13 x (8 x 11)

Step-by-step explanation:

Using the Associative Property

8 0
3 years ago
A lion runs at a speed of 50 mph and a cheetah runs 78 mph. If they both run at a steady rate, how far will a cheetah run in the
Elden [556K]

Answer:

21.45 mi

Step-by-step explanation:

Distance = speed × time

The time it takes the lion is:

13.75 mi = 50 mi/hr × t

t = 0.275 hr

The distance ran by the cheetah in that time is:

d = 78 mi/hr × 0.275 hr

d = 21.45 mi

7 0
3 years ago
Read 2 more answers
An iceberg weighs 450,000 lb. If it loses 0.2% of its weight during the day, what is its new weight at the end of the day?
JulsSmile [24]

Answer: The weight of the iceberg at the end of the day will be 449,100 lbs.

Step-by-step explanation: The question is solved by first calculating what the loss of weight is during the day. The question indicates that it will lose .2%. In order to calculate the loss you need to multiply 450,000 x .002, which equals 900. Next, we subtract the weight loss from the original weight to determine the end of day weight. 450,000 - 900 = 449,100 lbs.

6 0
3 years ago
Read 2 more answers
A submarine was twenty feet below the surface of the water and
Korolek [52]

Answer:

c 52.5 feet below

Step-by-step explanation:

6 0
3 years ago
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management
dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1=  13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12  in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0
3 years ago
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