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Monica [59]
3 years ago
15

What does 11/100 + 16/10 equal?

Mathematics
1 answer:
erastova [34]3 years ago
7 0
<span>11/100 + 16/10 equals 1.71, or as a fraction, 1 71/100.</span>
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Help! (math and area.) i'll give you brainliest!
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Help to solve -7 - 3a = 1 - 4a
Evgesh-ka [11]

Answer:

-7 - 3a = 1 – 4a  

Step one: Add 4a to -3a  

 

-7 + a = 1  

 

Step two: Add 7 to 1  

 

A = 8  

 

You're done! A=8 for this problem!  

 

 

Hopefully this helps! Feel free to mark brainliest!  

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A television normally sells for $320. This week, it's on sale at 60% of the normal price. What is the sale price?
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Find the exact value of tan(165°) using a difference of two angles
Katyanochek1 [597]

Answer:  -2+\sqrt{3}

=========================================================

Work Shown:

Apply the following trig identity

\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\

Now let's rationalize the denominator

\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as \sqrt{3}-2 but it's the same as above.

5 0
3 years ago
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