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3 years ago

Which of the following scenarios exhibits a function relation? Take the first set listed to be the domain of the relation.

1 answer:

3 0

D. The set of people with Social Security Cards and the set of Social Security numbers.
Is the scenario that exhibits a function relation.

A function is a set of ordered pairs wherein each x-element has only ONE y-element associated with it.

Choice D is a function because only one person corresponds to a single specific social security number.

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A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a

Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.5$

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 4) + P(X > 4) = 1$

We want to find $P(X > 4)$ . So

$P(X > 4) = 1 - P(X \leq 4)$

In which

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061$

$P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854$

$P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056$

$P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222$

$P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898$

Finally

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102$

91.02% probability of selling more than 4 properties in one week.

8 0

3 years ago

Find the slope of the line that passes through (6 , 2) and ( 1 ,10).

DochEvi [55]

Answer: Slope: -1.6

Use the slope formula

substitute point values in the formula

(10 -2)

- like this: m = ----------

(1 - 6)

Simplify each other side of the equation

- simplified: 8/-5

m: - 1.6

7 0

3 years ago

Please please help me out with this!!!!

Bess [88]

Answer:

y = - 6x

Step-by-step explanation:

Note the relation between x and y points on the table, that is

x = - 2 → y = 12

x = - 1 → y = 6

x = 1 → y = - 6

x = 2 → y = - 12

x = 3 → y = - 18

By inspection the y points are x multiplied by - 6, hence

y = - 6x ← is the equation relating x and y

7 0

2 years ago

Read 2 more answers

Question 3 of 10

gulaghasi [49]

Answer:

A, D and C.

Step-by-step explanation:

8 0

2 years ago

What is one 1whole 9/10 divided by 2/3

sasho [114]

Answer:

9/10=0

2/3=0

I don't know but I tried

4 0

2 years ago