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AlexFokin [52]
3 years ago
12

Exhibit 5-3 The probability distribution for the number of goals the Lions soccer team makes per game is given below. Number of

Goals Probability 0 .05 1 .15 2 .35 3 .30 4 .15 ​ Refer to Exhibit 5-3. What is the probability that in a given game the Lions will score less than 3 goals?
Mathematics
1 answer:
ioda3 years ago
8 0

Answer:

0.55 is the probability that Lions will score less than 3 goals.

Step-by-step explanation:

We are given the following in the question:

Number of goals(x):         0         1           2         3          4

             Probability:      0.05     0.15     0.35     0.30     0.25

We have to find the probability that Lions will score less than 3 goals.

P(X

0.55 is the probability that Lions will score less than 3 goals.

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garri49 [273]
Check out Desmos.com graphing calculator if you need help with graphing
4 0
3 years ago
I need help fast pleasee
trapecia [35]

Answer:

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

Step-by-step explanation:

y = A cos ( Bx + C) + D

Vertical shift D = 0

A = - 1

Compression / Stretching B

Period of given function is \frac{8\pi }{3}

Period of cos x is 2π

\frac{8\pi }{3} = \frac{2\pi }{B} ⇒ B = \frac{3}{4}

Horizontal shift is C ÷ B

Horizontal shift of given function is \frac{\pi }{3}

\frac{\pi }{3} = C ÷ \frac{3}{4} ⇒ C = \frac{\pi }{4}

So, the equation of given function is

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

4 0
2 years ago
A data scientist studying a manufacturing process classifies each item produced by the process as either Poor, Acceptable, or Ex
Genrish500 [490]

Answer:

0.214 ; 0.064 ; 0.3859 ; 0.9966 ; 0.135

Step-by-step explanation:

Given the distribution :

Poor ___ Acceptable ____ Excellent

0.25 _____ 0.6 _________ 0.15

The data scientist receives three items produced by the manufacturing process.

Find the chance that:

a. all of items are Acceptable

0.6 * 0.6 * 0.6 = 0.6^3 = 0.214

b. none of the items is Acceptable

P(not acceptable) = 1 - p(acceptable) = 1 - 0.6 = 0.4

0.4 * 0.4 * 0.4 = 0.4^3 = 0.064

c. at least one of the items is Excellent

P(atleast one) = 1 - P(none)

P(not excellent) = 1 - 0.15 = 0.85

P(none is excellent) = 0.85^3 = 0.614125

Hence,

P(atleast one is excellent) = 1 - 0.614125 = 0.3859

d. not all of the items are Excellent

P(not all) = 1 - p(All)

P(all excellent) = 0.15^3 = 0.003375

P(not all are excellent) = 1 - 0.003375 = 0.9966

e. there is one item of each class:

P(poor) * p(acceptable) * p(excellent) * (number of classes)!

0.25 * 0.6 * 0.15 * 3!

= 0.135

3 0
3 years ago
DAY 2 please help i dont get it
MrRa [10]
G because she need to sell 20 vases because the cost is 450 and if you divide it by 23 for the price the vases will be sold for it comes to 19.57 and you can't sell .57 of a vase you have to round up to make more than the money spent
3 0
3 years ago
1.
olchik [2.2K]
To solve this we are going to use the future value of annuity ordinary formula: FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
where
FV is the future value
P is the periodic payment
r is the interest rate in decimal form
n is the number of times the interest is compounded per year
k is the number of payments per year
t is the number of years

We know for our problem that P=6200 and t=5. To convert the interest rate to decimal form, we are going to divide the rate by 100%:
r= \frac{6}{100} =0.06
Since the deposit is made semiannually, it is made 2 times per year, so k=2.
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so n=2.
Lets replace the values in our formula:

FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]
FV=71076.06

We can conclude that the correct answer is <span>$71,076.06</span>
8 0
2 years ago
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