Answer: Stephon can buy total 4 chips bag and 2 candy bar
Step-by-step explanation:Given as :
The money which Stephon has in his pocket = $ 12
The cost of one chips bag = $ 2.25
The cost of one candy bar = $ 1.50
The total number of items he can buy = 6
So, Let the number of chips bag he can buy = x
∴ The number of candy bar he can buy = 6 - x
Now, according to question
The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12
Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12
Or, x × $ 2.25 + 9 - x × $ 1.50 = $ 12
or, x × $ 0.75 = 12 - 9
or, x = = 4
The number of chips bag he can buy = x = 4
And The number of candy bar he can buy = 6 - x = 6 - 4 = 2
Hence Stephon can buy total 4 chips bag and 2 candy bar .
Answer: y + 2 = 
( x - 4 )
Step-by-step explanation:
The equation of a line in point - slope form is given as ;
y - 
= m (x - 
)
= 4
= -2
m =
Substitute the values into the equation , we have
y - (-2) = ( x - 4 )
y + 2 = ( x - 4 )
Which could be written as :
y + 2 = y + 2 = x + 2
Answer:
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Answer:
a = 9
Step-by-step explanation:
First we need to add (x^2+3x) to (3x^2+ax),
(x^2+3x)+(3x^2+ax)
Expand
= x^2+3x+3x^2+ax
Collect the like terms
= x^2+3x^2+3x+ax
= 4x^2 + 3x + ax
= 4x^2+(3+a)x
Equate the solution to 4x^2+12x
4x^2+(3+a)x = 4x^2+12x
Comparing the like terms on both sides
(3+a)x =12x
3 + a = 12
a = 12 - 3
a = 9
Hence the value of a is 9
Remark
It looks like all you want is question 6. If that is the case, there are two ways to do it.
Algebra
<u>First answer</u>
abs(b - 22) = 5 Equate to + 5
b - 22 = 5 Add 22 to both sides.
b = 5 + 22
b = 27
<u>Second Answer</u>
Equate to - 5
b - 22 = -5
b = 22 - 5
b = 17
Method Two
<u>Graph the question</u>
The graph y = abs(b - 22) is shown below in red.
The values of y when y =5 are shown in blue.
