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snow_tiger [21]
3 years ago
15

How can I estimate the square root of a non-perfect square

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0
Hope this helped you :)
allsm [11]3 years ago
3 0
Use the two perfect squares it falls between to give you an accurate point of reference. 

For example, \/```28 (square root of 28)
The square root of 28 falls between the square root of 25 and 36, so you know the value will be between 5 and 6.
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a rectangle has a perimeter of 88cm. if the height is three times the length of the width what are the dimensions of the rectang
fredd [130]

Answer:

P=88. L=3w

P= 2(w)+2(L)

Then substitute the values into the equation

88=2w+2(3w)

Then solve for w and its length which is 3w

5 0
3 years ago
Which value is a discontinuity of x^2+7x+1/x^2+2x-15? x=-1 x=-2 x=-5 x=-4
dsp73
\dfrac{x^2+7x+1}{x^2+2x-15}=\dfrac{x^2+7x+1}{(x+5)(x-3)}

which is undefined when x=-5 or x=3. The answer is then the third choice.
6 0
4 years ago
7 POINTS!!! EASY!!BUT I AM SMALL. A skateboarder traveled 3 5 of a mile in 1 20 of an hour. What was the skateboarder’s speed in
Alex17521 [72]
Speed = distance ÷ time so it's probably
35÷120=0.291 or 7/24 miles per hour
7 0
3 years ago
Read 2 more answers
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
3 years ago
- A contractor plans to build a rectangular office complex. The floor area on the first floor of the
Neko [114]

Answer:

Width = 30

Step-by-step explanation:

Area = 18x * 10y = 180xy

Length = 6xy

Width = ?

Since the shape of the office complex is a rectangle,

Area of a rectangle = length × width

180xy = 6xy × width

Width = 180xy / 6xy

Width = 30

4 0
3 years ago
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