How can I estimate the square root of a non-perfect square

Mathematics

2 answers:

BlackZzzverrR [31]2 years ago

8 0

Hope this helped you :)

allsm [11]2 years ago

3 0

Use the two perfect squares it falls between to give you an accurate point of reference.

For example, \/```28 (square root of 28)
The square root of 28 falls between the square root of 25 and 36, so you know the value will be between 5 and 6.

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2 years ago

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Step-by-step explanation:

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30 POINTS,NEED HELP ASAP !!!

zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

$C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)$

And in the figure C'D'E'F' the vertices are:

$C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)$

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

$\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4$

Let's choose another vertex. For E'(8,8) and E(2,2):

$\frac{8}{2}=4\\\\\frac{8}{2}=4$

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

$(x, y)$ → $(4x, 4y)$