To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Answer:
6
Step-by-step explanation:
Answer:
Two line are perpendicular when they are at right angles to each other.
The red line is perpendicular to the blue line in each of these examples:
Perpendicular Example
Step-by-step ex;planation:
Answer:
6 miles
Step-by-step explanation:
first thing you need to do is find a number under 18 that can be multiplied by 3
3
6
9
12
15
18
and 18 is the 6th number and is 18, you can add the 2 extra fixed charge to that
they can travel 6 miles
but if you're talking about a fixed charge per mile then dont use this! ^^
<span>8 minutes 20 seconds.
First, lets determine who many miles per minute each vehicle moves by dividing each speed by 60.
Speeder = 60 / 60 = 1 mile per minute.
Police = 75 / 60 = 1.25 miles per minute.
Other car = 45 / 60 = 0.75 miles per minute.
Since the speeding car moves for 5 minutes before the police start to chase, that means that the speeding car will now be 5 + T miles down the road with T being the time the police has been chasing. The police will be 1.25 T. We're looking for when those two equations equal each other. So
5 + T = 1.25 T
Subtract T from both sides
5 = 0.25T
Divide both sides by 0.25
20 = T
So it will take the police officer 20 minutes to catch up to the speeder. And they will both have traveled a total distance of 25 miles from the point where the speeder passed the police car.
Now we need to figure out how far the law obeying car has moved during those 25 minutes. So
25 * 0.75 = 18.75 miles.
The distance the law obeying car needs to travel to catch up to the police officer then becomes
25 - 18.75 = 6.25 miles.
The number of minutes that the law obeying car needs to travel that distance is
6.25 / 0.75 = 8.333....
Which is 8 minutes 20 seconds.</span>
