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devlian [24]
3 years ago
6

Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x + 4 6x + 3y =

-12 -4 4 12
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
5 0

Answer:

Option (4)

Step-by-step explanation:

The given system of equations is,

y = -2x + 4 ------ (1)

6x + 3y = a --------(2)

We have to find the value of a for which the system of equations will have infinitely many solutions.

Option (1). If a = -12

                6x + 3y = -12

                2x + y = -4

                        y = -2x - 4

Both the equations have same slope, therefore, they are parallel and will have no solutions.

Option (2). If a = -4

                 6x + 3y = -4

                         3y = -6x - 4

                           y=-2x-\frac{4}{3}

Then equation (1) and (2) will intersect each other at least at one point Or there is exactly one solution of the system of the equations.

Option (3). If a = 4

                 6x + 3y = 4

                         3y = -6x + 4

                           y = -2x + \frac{4}{3}

Then equation (1) and (2) will intersect each other at least at one point Or there is exactly one solution of the system of the equations.

Option (4). If a = 12

                  6x + 3y = 12

                           3y = -6x + 12

                             y = -2x + 4

Therefore, both the equations (1) and (2) are same for a = 12 and they will have infinitely many solutions.

pshichka [43]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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Find the Area of the Shaded Region.
Mrac [35]

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Answer:

  610 m²

Step-by-step explanation:

If we extend the horizontal line across the right-hand portion of the figure, then the figure is divided into two rectangles:

  bottom: 5 m × 50 m = 250 m²

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The sum of these areas is the shaded area:

  shaded area = 250 m² +360 m² = 610 m²

4 0
2 years ago
550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,
EastWind [94]

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Answer:

  • adult: 325
  • children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

  1.50a +1.00(550 -a) = 712.50

  0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

  a = 325

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325 adult and 225 children's tickets were sold.

4 0
2 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

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Answer:

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Step-by-step explanation:

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