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3 years ago

C-c+a+ |a|; use a = 4, and c=5

Mathematics

1 answer:

Ulleksa [173]3 years ago

5 0

Answer:

c-c+a+|a|

5-5+4+|4|

Step-by-step explanation:

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In a 30° - 60° - 90° right triangle, the hypotenuse has a length of 8. what is the length of the longer leg?

Tatiana [17]

Sin 30° = 1/2 = x/8
then x = 4

sin 60° = √3/2 = y/8
then y = 4√3

so the length of the longer leg is 4√3

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3 years ago

Peter is writing a number in scientific notation.The number is grater that ten million and less that one hundred million.Which e

OLga [1]

Answer:

$M = a \times 10^7$ where 1 < a ≤ 9

The EXPONENT USED BY PETER is 7 in all the possible cases.

Step-by-step explanation:

Let us assume the needed number is M.

Also, given:

The needed number is GREATER than 10 Million.

⇒ M > 10 Million

⇒ M > 10,000,000

⇒ M > $1 \times 10^7$ ...... (1)

The needed number is SMALLER than 100 Million.

⇒ M < 100 Million

⇒ M < 100,000,000

⇒ M < $1 \times 10^8$ ...... (2)

Comparing (1) and (2) we can see that M can have more than 7 zeroes after 1 but LESS than 8 zeroes after 1.

So, the possible values of M can be:

$M = a \times 10^7$ where 1 < a ≤ 9

So, the EXPONENT USED BY PETER is 7 in all the possible cases.

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3 years ago

Five cats ate 1/4 cup of food how much food did five cats eat

Maslowich

If it was EACH cat they had 1.25 cups otherwise they all shared the 1/4 cup offered.

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3 years ago

What is another way to write the expression t⋅(14−5) ?

grigory [225]

t⋅(14−5)

distribute

14t -5t

Choice A

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3 years ago

Read 2 more answers

Find the volume of the wedge-shaped region contained in the cylinder x2 + y2 = 49, bounded above by the plane z = x and below by

fiasKO [112]

$\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy$

Converting to cylindrical coordinates, the integral is equivalent to

$\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta$
$=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)$
$=\dfrac{2\times7^3}3=\dfrac{686}3$

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3 years ago