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cupoosta [38]
3 years ago
5

The weights of the fish in a certain lake are normally distributed with a mean of 19 lb and a standard deviation of 6. If 4 fish

are randomly selected, what is the probability that the mean weight will be between 16.6 and 22.6 lb
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

67.30% probability that the mean weight will be between 16.6 and 22.6 lb

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 19, \sigma = 6, n = 4, s = \frac{6}{\sqrt{4}} = 3

If 4 fish are randomly selected, what is the probability that the mean weight will be between 16.6 and 22.6 lb

This is the pvalue of Z when X = 22.6 subtracted by the pvalue of Z when X = 16.6.

X = 22.6

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22.6 - 19}{3}

Z = 1.2

Z = 1.2 has a pvalue of 0.8849

X = 16.6

Z = \frac{X - \mu}{s}

Z = \frac{16.6 - 19}{3}

Z = -0.8

Z = -0.8 has a pvalue of 0.2119

0.8849 - 0.2119 = 0.6730

67.30% probability that the mean weight will be between 16.6 and 22.6 lb

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