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erastovalidia [21]
3 years ago
5

What is the amplitude of the function graphed? Enter your answer in the box.

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
8. Amplitude is the amount of boxes or points or numbers between the highest point and lowest point on the graph
You might be interested in
How to solve for -3x squared + 2y squared + 5xy - 2y + 5x squared - 3y squared when x = 0.5 and y = -1/10??
Pani-rosa [81]

Answer:

0.44

Step-by-step explanation:

-3x^2 + 2y^2 + 5xy - 2y +5x^2 - 3y^2

Combine like terms

-3x^2 + 5x^2 = 2x^2 2y^2 - 3y^2 = -1y^2

2x^2 - 1y^2 + 5xy - 2y

Now plug in the solutions Note: it is easier if you have all decimals or all fractions (-1/10=-.1

2(0.5)^2 - 1(-0.1)^2 + 5(0.5)(-0.1) - 2(-0.1)

Simplify:

0.5 - 0.01 - 0.25 + 0.2

0.5 + 0.2 - 0.01 - 0.25

0.7 - 0.26

0.44

5 0
3 years ago
50-0<br> ———(12.0-0) +0 = <br> 12.0-0 <br><br> Just a warm up
vagabundo [1.1K]

\frac{50}{12} x 12

the 12 in the numerator (top) and the 12 in the denominator (bottom) cross out so you are left with 50.

Answer: 50

8 0
3 years ago
Read 2 more answers
the equation y equals 0.25 x describes a proportional relationship between X and Y what is the constant of proportionality
Fittoniya [83]
The constant of proportionality is for every 1 x, there is 0.25 y. y = 0.25, and on a graph, x is always the "1." Since x is worth 1, y must be worth 0.25.
4 0
3 years ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
Read 2 more answers
Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.
melomori [17]
V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C
</span>
4 0
3 years ago
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