Margo can purchase tile at a store for $0.99 per tile and rent a tile saw for $18. At another store she can borrow the tile saw
1 answer:
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Answer: 3.217 & 12.434
Step-by-step explanation:
If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.
Hence, the length is .
The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.
We can also substitute 40 in for A as it's given in the question.
Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get
We can make the equation simpler by dividing both sides by 2.
Subtracting both sides by 20 will make the left-hand side 0.
Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.
For reference, the quadratic formula is
In this case, a is 1, b is 3, and c is -20.
Substituting, we get
Since the second solution results in a negative number, it cannot be the length of w.
The width/breadth of the rectangle is 3.217 cm.
To calculate the length, let's substitute the width into the expression for the length:
The length of this rectangle is 12.434 cm.
Question:
The available options are:
(A) There is convincing evidence that there is no difference in the mean delivery times.
(B) There is convincing evidence that there is a difference in the mean delivery times.
(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.
(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan. (E) The t-test cannot be used for sample sizes that are this small.
Answer:
The correct option is;
(A) There is convincing evidence that there is no difference in the mean delivery times.
Step-by-step explanation:
Here we have the formula for the two-sample t-test given s;
To Texas N₁ = 12, =8.74 σ₁ = 2.92 SE Mean₁ = 0.84
To Japan N₂ = 9 = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85
t = 1.667
Where the null hypothesis is
mu To Texas = mu To Japan and the alternative is
mu To Texas > mu To Japan
Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.
Hence, there is convincing evidence that there is no difference in the mean delivery times.