Answer:
15
Step-by-step explanation:
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
y = -53/2, x = -17
Step-by-step explanation:
1/2x + 3/2 = -7
-3x +2y = -2
Isolate X for 1/2x + 3/2 = -7
X = -17
Substitute X = -17
-3(-17) + 2y = -2
Isolate Y for -3 (-17) + 2y = -2
Y = -53/2
