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2 years ago

Hiii I need help with this question!! 1.10.4 TEST coordinate geometry!

Mathematics

1 answer:

KatRina [158]2 years ago

6 0

Formula

$\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}$

<h3>Solution:-1</h3>

(5,7)
(-4,-2)

$\\ \sf\longmapsto m=\dfrac{-2-7}{-4-5}$

$\\ \sf\longmapsto m=\dfrac{-9}{-9}$

$\\ \sf\longmapsto m=1$

<h3>Solution:-2</h3>

(1,3)
(1,-10)

$\\ \sf\longmapsto m=\dfrac{-10-3}{1-1}$

$\\ \sf\longmapsto m=\dfrac{-13}{0}$

$\\ \sf\longmapsto m=0$

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seropon [69]

Given:

32 and 28 are the two numbers.

To find:

(a) The GCF of 32 and 28.

(b) Using the GCF, find the factor of (32-28).

Solution:

(a)

The factor forms of the given numbers are:

$32=2\times 2\times 2\times 2\times 2$

$28=2\times 2\times 7$

It is clear that, 2 and 2 are the common factors in both.

$GCF(32,28)=2\times 2$

$GCF(32,28)=4$

Hence, the GCF of 32 and 28 is 4.

(b)

Using the GCF we need to find the factor of (32-28).

$32-28=4\times 8-4\times 7$

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$32-28=4\times (8-7)$

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2 years ago