Answer:
One kids ticket is $4.80 and one adult ticket is $9.60
Step-by-step explanation:
Create a system of equations where k is the cost of a kids ticket and a is the cost of an adult ticket:
6k + 2a = 48
k = 1/2a
Solve by substitution by substituting the second equation into the first one:
6k + 2a = 48
6(1/2a) + 2a = 48
Simplify and solve for a:
3a + 2a = 48
5a = 48
a = 9.6
Find the cost of a kids ticket by dividing this by 2, since they are on sale for half the price of adult tickets.
9.6/2
= 4.8
One kids ticket is $4.80 and one adult ticket is $9.60
<u>To solve this problem, we must consider all the trigonometric equations</u>:
⇒ (<em>see image below)</em>
<u>Let's examine the diagram</u>:
- the side adjacent to ∠A ⇒ AC ⇒ 35 meters
- hypotenuse ⇒ 53 meters
<u>Thus we can use:</u>
![cos(A)=\frac{35}{53} \\A= cos^{-1}(\frac{35}{53})\\ A = 48.67](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B35%7D%7B53%7D%20%5C%5CA%3D%20cos%5E%7B-1%7D%28%5Cfrac%7B35%7D%7B53%7D%29%5C%5C%20A%20%3D%2048.67)
<u>Answer: 49 degrees</u> <em>(as rounded)</em>
Hope that helps!
Answer:roughly around 70 yards since a whole foot ball field including the the touch down is about 120 yards I think
Step-by-step explanation:
Hi! May I ask where is your answer choices?
<span>So, the volume of a container can also be thought of as the amount of liquid that the container is capable of holding. It follows that 450=(length)(width)(height). The constraints of the problem say that the length of the box must be twice as large as the width, so it follows that j(height)=(2w)(w)(height)-450. This then implies that j(height)=(2w^2)(height)-450. In simpler terms, the height is defined as 450/(2w^2), or j(w)=450/(2w^2).</span>