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Hunter-Best [27]
3 years ago
10

Jorgen Grace made deposits of $250 at the end of each year for 12 years. The rate received was 6% annually. What is the value of

the investment after 12 years?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0
<span>Deposits made is $250, it is called Present value P = 250 Rate of interest r = 6% = 0.06 Time n = 12 years, 12 payments Investment value after n years FV = FV = P *(1+r) *(((1+r) ^ n) – 1)/r FV = 250 * (1 + 0.06) * (((1 + 0.06)^12) - 1)/0.06 FV = 250 * 1.06 * (((1.06)^12) - 1)/0.06 => FV = 250 * 1.06 * (2.012 - 1)/0.06 FV = 250 * 1.06 * 1.012/0.06 => FV = 250 * 1.06 * 16.87 FV = 250 * 17.88 => FV = 4470.5 So the final value of investment after 12 years is $4470.5.</span>
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Which property is shown by -6+0=-6?
Rashid [163]
B. Identity Property of Addition

The Identity Property of Addition states that the sum of any number and zero will always be the first number. So -6 + 0 = -6 shows the Identity Property of Addition.
8 0
2 years ago
Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​
pochemuha

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - \frac{b}{a} = \frac{5}{2}

product of roots = \frac{c}{a} = - 3, then

sum of new roots = \frac{1}{\alpha } + \frac{1}{\beta }

= \frac{\beta+\alpha  }{\alpha \beta }

= \frac{\frac{5}{2} }{-3} = - \frac{5}{6}

product of new roots = \frac{1}{\alpha } × \frac{1}{\beta }

= \frac{1}{\alpha\beta  } = - \frac{1}{3}

Hence the required equation is

x² + \frac{5}{6} x - \frac{1}{3} = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

                           

8 0
3 years ago
A rectangular yard measuring 39 ft by 67 ft is bordered (and surrounded) by a fence. Inside, a walk that is 4 ft wide goes all t
Gekata [30.6K]

The area of the walk is 784 square feet

<h3>What is an area?</h3>

Area is the quantity that expresses the extent of a region on the plane or on a curved surface

First, calculate the area of the rectangular yard.

Area = L x W    

where A equals area, L equals length, and W equals width.

According to the stated problem:

A = 39 x 67

A = 2613 square feet          <-------Area of Rectangular yard.

Now, according to the stated problem there is a walk that is 4 feet wide going all the way along the fence (Inside). "

Therefore, we have 8 feet to subtract from each of the values above (39) and (67).

That is 4 feet on each side,

A = L x W

A = 31 x 59

A = 1829 square feet     <----------Area of new rectangle formed by allowing for three foot walk.

Now, subtract the area of the new rectangle formed from the area of the original area. Doing so, will give you the area of the walk, correct?

Original area    =  2613  square feet

New area         =   1829 square feet

Hence, the Area of WALK = 784 square feet

Learn more about  area on: brainly.com/question/22972014

#SPJ1

3 0
1 year ago
Write the equation of the line that is parallel to y=2x+2 and goes through points (4,5)
kari74 [83]
Y = 2x-3
The second line will have its Y-Intercept at -3 and its slope will be up 2 and over 1 which will allow it to go through (4,5) and the line will be parallel to Y = 2x+2
7 0
3 years ago
Am i right?? please help!
ladessa [460]

Answer: yes

Step-by-step explanation:

5 0
3 years ago
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