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olga2289 [7]
3 years ago
7

Select the equation in which the graph of the line has a positive slope, and the y-intercept equals -8.

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0
The second one. 10x - 5y = 40
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Isabelle rides her bike to school. The graph shows her speed at different point
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Answer:

0 to 2 minutes - Accelerating

3 to 4 minutes - Constant

6 to 8 minutes - Decelerating

9 to 11 minutes Accelerating

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Step-by-step explanation:

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What was life like in Hargigo before people planted the mangrove trees?
Mamont248 [21]

Answer:

Step-by-step explanation:

That is until they met Dr. Gordon Sato who had an idea of how to help them. He proposed that Hargigo plant mangrove trees near the sea because ... From this one mangrove tree grew many, and these trees gave the people of Hargigo hope. ... They really brought the story of the mangrove trees to life.

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3 years ago
You are dealt one card from a 52-card deck. find the probability that you are not dealt: a heart.
Nadya [2.5K]
3/4 or 75% chance you're not dealt a heart
5 0
3 years ago
If y = 4x – 1, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
Helga [31]
Hello!

To do this you will pick an x value, multiply it by the slope and add the y- intercept. Let's try 0.

y=4(0)-1
y=-1

So here, an ordered pair could be (0,-1)

We can try this again for different x-values.

y=4(1)-1
y=3

This gives us the ordered pair  (1,3)

y=4(100)-1
y=399

This would give us the ordered pair (100,399)

I hope this helps!
6 0
3 years ago
What are the first, second, and third frequencies audible from a 20 cm long organ pipe when (A) only one end is open and when (B
kotykmax [81]
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz

The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz


2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz


3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz


B) The answers are:

the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz

The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz


2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz


3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
4 0
3 years ago
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