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olga2289 [7]
3 years ago
7

Select the equation in which the graph of the line has a positive slope, and the y-intercept equals -8.

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0
The second one. 10x - 5y = 40
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A square is a type of
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A square is a type of quadrilateral. 
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3 years ago
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What is the area of the figure? <br> A) 18 yd2 <br> B) 54 yd2 <br> C) 72 yd2 <br> D) 90 yd2
den301095 [7]

Answer:

<em><u>7</u></em><em><u>2</u></em><em><u> </u></em><em><u>yd²</u></em>

Step-by-step explanation:

area of this figure = area of 1st rectangle + area of 2nd rectangle

= l×b + L×B

= 6 × 5 + 14 × 3

=30 + 42

= 72 yd²

4 0
2 years ago
Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6. Type your answer in the
san4es73 [151]
Rewrite the equation: 2y=x-6, y=x/2-3, so slope is 1/2 which is also the slope of the parallel line.
It will have the equation y=x/2+a where a is found by plugging in the given point: 4=-1+a, so a=5.
Therefore y=x/2+5. (This can also be written 2y=x+10 or x-2y+10=0)
5 0
3 years ago
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Equation of the line (-6,5) and (8,14) in standard form
blsea [12.9K]

Answer:

\huge\boxed{9x-14y=-70}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, 5) and (8, 14).

Substitute:

m=\dfrac{14-5}{8-(-6)}=\dfrac{9}{14}\\\\y-5=\dfrac{9}{14}(x-(-6))\\\\y-5=\dfrac{9}{14}(x+6)

Thew standard form of an equation of a line:

Ax+By=C

transform:

y-5=\dfrac{9}{14}(x+6)\qquad|\text{multiply both sides by 14}\\\\14y-14\cdot5=14\!\!\!\!\!\diagup^1\cdot\dfrac{9}{14\!\!\!\!\!\diagup_1}(x+6)\\\\14y-70=9(x+6)\\\\14y-70=9x+54\qquad|\text{subtract}\ 9x\ \text{from both sides}\\\\-9x+14y-70=54\qquad|\text{add 70 to both sides}\\\\-9x+14y=70\qquad|\text{change the signs}\\\\9x-14y=-70

4 0
3 years ago
What would the answer be to 1/2+1/8-1/4
Inga [223]
The answer for that equation will be 0.375.
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3 years ago
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