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Natali5045456 [20]
3 years ago
11

Help please! show your steps please​

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

x = -9

Step-by-step explanation:

<em>To solve the equation</em>

  • Simplify each side
  • Separate the variable on one side and the numerical term on the other side
  • Make the coefficient of the variable equal 1

<em>Let us do these steps with our question to find x</em>

∵ 4(2x + 7) = 12 - 2(10 - 2x)

→ Simplify each side

∵ 4(2x) + 4(7) = 12 - 2(10) - 2(-2x)

∴ 8x + 28 = 12 - 20 + 4x

→ Add the like terms in the right side

∵ 8x + 28 = (12 - 20) + 4x

∴ 8x + 28 = -8 + 4x

→ Subtract 28 from both sides

∵ 8x + 28 - 28 = -8 - 28 + 4x

∴ 8x = -36 + 4x

→ Subtract 4x from both sides

∵ 8x - 4x = -36 + 4x - 4x

∴ 4x = -36

→ Make coefficient of x equal 1 by dividing both sides by 4

∴ \frac{4x}{4}=\frac{-36}{4}

∴ x = -9

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Solve the following ODE's: c) y* - 9y' + 18y = t^2
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y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

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C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

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3 years ago
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