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Veseljchak [2.6K]
2 years ago
7

What is the area in square meters of 6 triangles. how many triangles are needed to compose a region that is 1 1\2 square meters?

Mathematics
1 answer:
Delicious77 [7]2 years ago
8 0

To create an area that is 1.5 m^2   in size, you will need to make use of a total of 27 triangles.

<h3>How many triangles are needed to compose a region that is 1.5 square meters?</h3>

A square that has a size of one square meter is divided into nine smaller squares that are similar to each other. Each of the little squares is divided into two triangles that are similar to one another.

There are nine smaller squares contained inside one square meter, since 1 square meter may be broken down into nine identical smaller squares. Each of the little squares is divided into two triangles that are similar to one another. 9 smaller squares may be broken down into the following:

9*2=18 (shows identical triangles)

Hence, 1 square meter is decomposed into 18 identical triangles.

We need to find the number of triangles needed to compose a region that is square meters

where

m^2 = 1.5 m^2

Where

1 m^2 = 18 identical triangles.

1.5 m^2 = 1.5 * 18

1.5 m^2  = 27 identical triangles.

In conclusion, To create an area that is 1.5 m^2   in size, you will need to make use of a total of 27 triangles.

Read more about the area

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3 years ago
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Answer:

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Step-by-step explanation:

Note that this is a large triangle with 2 smaller, similar triangles inside.  The base of the large triangle is 10, so the base of either of the smaller triangles is half that, or 5.  These are all right triangles.  We can now apply the Pythagorean Theorem to find x.

According to this Theorem, x² + 5² = 11², so that x² = 121 - 25 = 96.

Taking the positive square root to be the desired side length x,

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4 years ago
The widths of two similar rectangles have a ratio of 2:6 . The area of the smaller rectangle is 12 ft2. What is the area of the
Korolek [52]

Answer:

The area of the larger rectangle is 108\ ft^{2}

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its areas is equal to the scale factor  squared

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Let

z-----> the scale factor

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y-----> the area of larger rectangle

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z^{2} =\frac{x}{y}

we have

z=2/6

x=12\ ft^{2}

substitute  and solve for y

(2/6)^{2} =\frac{12}{y}

y=12/(4/36)=108\ ft^{2}

8 0
3 years ago
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Answer:

D) x - 7 + 3

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