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mojhsa [17]
3 years ago
10

Given right triangle JKM, which correctly describes the locations of the sides in relation to ∠J?

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

a is the hypotenuse, b is adjacent, c is opposite

Step-by-step explanation:

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Please help me I’m struggling :’(
Vesna [10]

Answer:

B. x = \sqrt{40}

Step-by-step explanation:

Using Pythagorean theorem, find the value of x.

Pythagorean theorem is given as c^2 = a^2 + b^2

Where,

c is the longest side of a right angled ∆ = the hypotenuse = x

a and b are legs of the right angled ∆ = 2 and 6

Plug in the values into the equation and solve for x

x^2 = 2^2 + 6^2

x^2 = 4 + 36

x^2 = 40

x = \sqrt{40}

5 0
3 years ago
The length of a rectangle is 2 more than 3 times the width. if the perimeter is 100. find the length and with of the rectangle
Greeley [361]
A ihjerhvyugvehifsvyueuhwfutygw
4 0
3 years ago
Determine the total number of proper subsets of the set of letters from the English alphabet a,b, c, ...,j. The number of proper
Inga [223]
\{a,b,c,\ldots,j\} has ten elements, so any proper subset has at most nine of these elements.

The number of ways of taking any 0\le n\le 9 letters from this set is given by the binomial coefficient,

\dbinom{10}n=\dfrac{10!}{n!(10-n)!}

and in particular, the total number of ways to picking proper subsets is

\displaystyle\sum_{n=0}^9\binom{10}n=\dbinom{10}0+\dbinom{10}1+\cdots+\dbinom{10}9

Without computing each term directly, let's instead use a direct result from the binomial theorem, which says

\displaystyle\sum_{n=0}^N\binom Nna^nb^{N-n}=(a+b)^N

If we replace a=b=1, then we're left with

\displaystyle\sum_{n=0}^N\binom Nn=(1+1)^N=2^N

We can use this to evaluate our sum directly:

\displaystyle\sum_{n=0}^9\binom{10}n=\sum_{n=0}^{10}\binom{10}n-\binom{10}{10}=2^{10}-1=1023
8 0
3 years ago
For his phone service, Deshaun pays a monthly fee of $17, and he pays an additional $0.04 per minute of use. The least he has be
aleksley [76]
Not sure what you are looking for, but the difference between $67.44 & the monthly fee of $17 would be the cost of the charge of minutes he spent talking on the phone. 67.44 - 17.00 = $50.44

50.44/ .04 = 1,261 minutes he talked on the phone.
8 0
2 years ago
Pure acid is to be added to a 10% acid solution to obtain 90L of 81% solution. What amounts of each should be used?
Vlada [557]

Answer:

Step-by-step explanation:

let X be the quantity of 100% acid

let Y be the quantity of  10% acid

X + Y = 90

Y = 90 - X

         X(100) + Y(10) = 90(81)

X(100) + (90 - X)(10) = 90(81)

   100X + 900 - 10X = 7290

                         90X = 6390

                              X = 71 L

7 0
2 years ago
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