2 years ago

Given right triangle JKM, which correctly describes the locations of the sides in relation to ∠J?

Mathematics

1 answer:

Leto [7]2 years ago

6 0

Answer:

a is the hypotenuse, b is adjacent, c is opposite

Step-by-step explanation:

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A recipe for 3 cups of snack mix calls for 1··2cup of pretzels. You can describe this as 3 cups of snack mix for every 1··2cup o

lukranit [14]

Answer:

i do not know

Step-by-step explanation:

5 0

2 years ago

PLZZ HELP Fill in the blank with the correct response. The slope of the graph of y = x is ___a0.

Lesechka [4]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

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y = x ← is in slope- intercept form

with slope m = 1

6 0

2 years ago

Can you tell me what is 26-4s=9s

wariber [46]

26 - 4s = 9s
26 = 9s + 4s
26 = 13s
13s = 26
s = 26/13
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6 0

3 years ago

Read 2 more answers

In ACDE, the measure of E=90°, the measure of C=70°, and DE = 12 feet.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

12.8 feet

6 0

2 years ago

Select True or False for each statement.

SSSSS [86.1K]

$\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32$

TRUE

$\sqrt[5]{36^4}=36^{4/5}$

which surely isn't 36. FALSE

$\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0$

FALSE

For the fourth one we have a

$\sqrt{98b} + \sqrt{2b}$

which isnt

$10\sqrt{b}$

so this is FALSE.

$\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}$

$= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}$

$=(\sqrt 5 + \sqrt 6)^2$

No fractions in that one so FALSE.

3 0

2 years ago