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mojhsa [17]
2 years ago
10

Given right triangle JKM, which correctly describes the locations of the sides in relation to ∠J?

Mathematics
1 answer:
Leto [7]2 years ago
6 0

Answer:

a is the hypotenuse, b is adjacent, c is opposite

Step-by-step explanation:

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A recipe for 3 cups of snack mix calls for 1··2cup of pretzels. You can describe this as 3 cups of snack mix for every 1··2cup o
lukranit [14]

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i do not know

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5 0
2 years ago
PLZZ HELP Fill in the blank with the correct response. The slope of the graph of y = x is ___a0.
Lesechka [4]

Answer:

1

Step-by-step explanation:

The equation of a line in slope- intercept form is

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6 0
2 years ago
Can you tell me what is 26-4s=9s
wariber [46]
26 - 4s = 9s
26 = 9s + 4s
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6 0
3 years ago
Read 2 more answers
In ACDE, the measure of E=90°, the measure of C=70°, and DE = 12 feet.
Oksi-84 [34.3K]

Answer:

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12.8 feet

6 0
2 years ago
Select True or False for each statement.
SSSSS [86.1K]

\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32

TRUE

\sqrt[5]{36^4}=36^{4/5}

which surely isn't 36.  FALSE

\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0

FALSE

For the fourth one we have a

\sqrt{98b} + \sqrt{2b}

which isnt

10\sqrt{b}

so this is FALSE.

\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}

= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}

=(\sqrt 5 + \sqrt 6)^2

No fractions in that one so FALSE.

3 0
2 years ago
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