This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15
64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3
Answer:
f(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
Hope this helps! :)
Answer: 10%
Step-by-step explanation:
30/3 = 10
