-1 Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20
+
5
=
25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25
−
6
=
19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19
−
20
=
−
1
and this makes sense because we know we advanced 5 and fell back 6
Answer:
91
Step-by-step explanation:
In this question, the important information we get from this is that the stage can support 12,750 students. We are asked, if the average weight of a student is 140 pounds, what is the maximum number of students that can be on the stage safely?
To solve, we simply divide 12,750 by 140.


We get 91.07 as our answer. Since we are considering the maximum number of students, then we must round 91.07 to the nearest whole number which would be 91.
The maximum number of students who could safely be on the stage is 91.
Answer:
The expected amount of blue M&M's would be 15
Step-by-step explanation:
12% of 125 is 15 therefore you should expect 15.
Answer:

Step-by-step explanation:
the quadratic function should be as follows:

Now let's confirm that the zeros of the function are 0 and 8

Therefore we can see that if x = 0

the equation is fulfilled
And we also have 
for this expresion to be equal to zero:

thus, if x = 8

the equation is also fulfilled
The zeros of the quadratic function
are 0 and 8.
<span>2 times 10 squared to the second power in standard notation
2 x(10^2)^2
=2x10^4
=20000</span>