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katrin [286]
3 years ago
9

Bobby bought 3 5/12 fraction numerator 5 1/12 star times text end text over denominator $1.20 star times text end text end fract

ion ft of red ribbon and 5 fraction numerator 1 star times text end text over denominator 12 star times text end text end fraction ft of yellow ribbon. Ribbon costs Syntax error from line 1 column 87 to line 1 column 107. Unexpected '1'. a foot. How much did Bobby spend on ribbon?
Mathematics
1 answer:
TEA [102]3 years ago
6 0
Hey Ender, I'm pretty sure you got some text things wrong, or just copied and pasted something, because what you wrote there makes 0 sense :)

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Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak
crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28

We can now calculate the probabilities:

P(0.47

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2

We can now calculate the probabilities:

P(0.47

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

8 0
3 years ago
I will do anything plss asppp
AlexFokin [52]

Answer:

I think the answer is A

Step-by-step explanation:

Let me know if it is not

4 0
3 years ago
Urrent
Naily [24]

Answer:

The cost of 1000 bushels is $9790

Step-by-step explanation:

Given

Cost = \$9.79 per bushel

Required

Determine the cost of 1000 bushels

If 1 bushel costs $9.79,

Then 1000 costs:

Total = \$9.79 * 1000

Total = \$9790

3 0
2 years ago
What is 450 increased by 18%
Blababa [14]
450*(1+0.18)=531 hence 450 increased by 18% is 531
6 0
3 years ago
Read 2 more answers
James can mow a 1/6 acre and 8 minutes if her rate is constant can James Mow 1 1/2 acre in 1 hour explain​
yulyashka [42]

Answer: No

Step-by-step explanation: 1 1/2 divided by 1/6 = 9. Since he said he could mow 1/6 acre in 8 minutes, and he needed to mow 9 x 1/6 acre, we need to multiply 8x9 which equals 72. An hour is 60 minutes so he can't mow 1 1/2 acres in an hour.

5 0
3 years ago
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