A circle is centered at (2,-5) and has radius 3. Write its equation in standard form.

Mathematics

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

Option (D) is correct

$(x-2)^{2} +(y+5)^{2} = 9$

Step-by-step explanation:

A circle has (a , b ) are the coordinates of the centre and $r = radius$ .

Given.

A circle is centered at (2,-5) and has radius 3

Let $a=2$ and $b=-5$ and $r=3$

The standard form of the circle is.

$(x-a)^{2} +(y-b)^{2} = r^{2}$ ------(1)

Put a, b and r value in equation 1.

$(x-2)^{2} +(y-(-5))^{2}= 3^{2}$

$(x-2)^{2} +(y+5)^{2} = 9$

So. the standard form of equation is.

$(x-2)^{2} +(y+5)^{2}= 9$

You might be interested in

4/9 expressed as a percent please help and show work! Please

coldgirl [10]

4/9 as a percent is (about) 44% Work:
First get a decimal by dividing 4/9(4 divided by 9) you get 0.44 repeating
Next, take away the 0. and add a percent sign at the end of 0.44. You get 44%
Truly, the answer is 44.44444...% because the four repeats, but if you round it is simply 44%

7 0

3 years ago

Read 2 more answers

Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$