Question

A circle is centered at (2,-5) and has radius 3. Write its equation in standard form.

Answer 1

Answer:

Option (D) is correct

$(x-2)^{2} +(y+5)^{2} = 9$

Step-by-step explanation:

A circle has (a , b ) are the coordinates of the centre and $r = radius$ .

Given.

A circle is centered at (2,-5) and has radius 3

Let $a=2$ and $b=-5$ and $r=3$

The standard form of the circle is.

$(x-a)^{2} +(y-b)^{2} = r^{2}$------(1)

Put a, b and r value in equation  1.

$(x-2)^{2} +(y-(-5))^{2}= 3^{2}$

$(x-2)^{2} +(y+5)^{2} = 9$

So. the standard form of equation is.

$(x-2)^{2} +(y+5)^{2}= 9$