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3 years ago

A plot of rectangular land is divided into 3 sections, P.

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Perimeter = 2(l+b)

170 = 2(x+x+15)

170 = 2(2x+15)

170 = 4x+30

140 = 4x

x = 35 meters

Area = LxB => 35x(35+15)

Area = 35x(50)

Area = 1750 meters

Area of the largest plot = 1750/3

=> 583.'3' meters

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3 years ago

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How do I find domain and range from a graph/equation?

likoan [24]

domain represents the x values so for example in a diagonal line that continues infinitely, the domain is all real numbers or (-infinity, infinity)

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3 years ago

Draw a box plot for the following data. {35, 50, 50, 48, 48, 32, 38, 41, 48, 34, 29, 23, 41, 34, 43}

loris [4]

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7 0

4 years ago

8) The sides of a flower garden are shown in the diagram below. What is the perimeter of the flower garden? 4m 2 m

jeka94

Answer:

18.28 m

Step-by-step explanation:

Given the flower garden in the question :

The shape is composite and can be divided into 2 semicirles and rectangle

The perimeter of a semicircle is the Circumference of the semicircle = πr

Hence, 2 semicirles = 2πr

Radius of semicircle = 2/2 = 1

Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m

The perimeter of rectangle; length and width are 6m and 2 m respectively :

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Tve perimeter of garden = 6.28 + 12 = 18.28 m

8 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago