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3 years ago

A plot of rectangular land is divided into 3 sections, P.

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Perimeter = 2(l+b)

170 = 2(x+x+15)

170 = 2(2x+15)

170 = 4x+30

140 = 4x

x = 35 meters

Area = LxB => 35x(35+15)

Area = 35x(50)

Area = 1750 meters

Area of the largest plot = 1750/3

=> 583.'3' meters

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kolbaska11 [484]

7 because 4+2=6 and 1/2+1/2=1 so 6+1=7

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3 years ago

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A bicycle store costs $3300 per month to operate. The store pays an average of $75 per bike. The average selling price of each

Klio2033 [76]

S=Selling price 135
V=Variable cost 75
F=Fixed cost 3300
Let quantity be Q
The formula to break even is
135Q-75Q-3300=0
Solve for Q
60Q-3300=0
60Q=3300
Q=3300/60
Q=50
So the store must sell 50 bicycles to break even

Hope it helps!

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4 years ago

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Ill give brainliest

Rzqust [24]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}m+4n=8&(1)\\m=n-2&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\n-2+4n=8\qquad\text{add 2 to both sides}\\5n=10\qquad\text{divide both sides by 5}\\n=2\\\\\text{put the value of}\ n\ \text{to (2):}\\\\m=2-2\\m=0$

4 0

3 years ago

The goals against average (A) for a professional hockey goalie is determined using the formula A = 60 a equals 60 left-parenthes

Marina CMI [18]

Answer:

Option 1 - $\frac{At}{60}=g$

Step-by-step explanation:

Given : The goals against average (A) for a professional hockey goalie is determined using the formula $A=60(\frac{g}{t} )$ . In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes.

To find : Which is an equivalent equation solved for g?

Solution :

Solve the formula in terms of g,

$A=60(\frac{g}{t})$

Multiply both side by t,

$At=60g$

Divide both side by 60,

$\frac{At}{60}=\frac{60g}{60}$

$\frac{At}{60}=g$

Therefore, option 1 is correct.

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3 years ago

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A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3

fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

$\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7$

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2 years ago